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3 years ago

15

(-5) X ? =-15 find the missing number

2 answers:

likoan [24]3 years ago

5 0

Answer:

3

Step-by-step explanation:

(-5) × ? = (-15)

? = (-15)/(-5)

? = 3

VMariaS [17]3 years ago

4 0

<h3>Answer:</h3>

3

<h3>Step-by-step explanation:</h3>

(-5) × ? = -15

? = -15 ÷ (-5)

? = 15 ÷ 5

? = (3 × 3 × 3) <= 3 Factor

? = 3

<h3>Conclusion:</h3>

Value of ? is 3.

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Gelneren [198K]

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Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the gi

Lina20 [59]

Answer:

y=-4x-14

Step-by-step explanation:

Lines that are parallel would have the same slope, so the slope is

m= -4

Use point slope equation to solve for the slope intercept equation.

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3 years ago

Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

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Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

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$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

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nadya68 [22]

Answer:

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Step-by-step explanation:

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