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tigry1 [53]
3 years ago
11

Which of the following is the correct action to take when simplifying the expression (xy^2)^3

Mathematics
1 answer:
aliya0001 [1]3 years ago
7 0
<span>(xy^2)^3
= x^3y^6

answer
C. </span><span>apply the cube to both the x and the y^2</span>
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There is enough grass to feed 6 cows
tekilochka [14]

Answer:

And?

Step-by-step explanation:

4 0
3 years ago
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Factor the expression below x^2+12+36 A) (x-6)(x-6) B) (x+6)(x+6) C) (x-9)(x-4) D) (x+9)(x+4)
evablogger [386]

Answer:

Answer B

Step-by-step explanation:

when you simplify it u get x^2+12+36

4 0
3 years ago
In tests of a computer component, it is found that the mean time between failures is 937 hours. A modification is made which is
VladimirAG [237]

Answer:

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Test Statistics z = 2.65

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

P- value = 0.004025

Step-by-step explanation:

Given that:

Mean \overline x = 960 hours

Sample size n = 36

Mean population \mu = 937

Standard deviation \sigma = 52

Given that the mean  time between failures is 937 hours. The objective is to determine if the mean time between failures is greater than 937 hours

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Degree of freedom = n-1

Degree of freedom = 36-1

Degree of freedom = 35

The level of significance ∝ = 0.01

SInce the degree of freedom is 35 and the level of significance ∝ = 0.01;

from t-table t(0.99,35), the critical value = 2.438

The test statistics is :

Z = \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}}

Z = \dfrac{960-937 }{\dfrac{52}{\sqrt{36}}}

Z = \dfrac{23}{8.66}

Z = 2.65

The decision rule is to reject null hypothesis   if  test statistics is greater than  critical value.

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

The P-value can be calculated as follows:

find P(z < - 2.65) from normal distribution tables

= 1 - P (z ≤ 2.65)

= 1 - 0.995975     (using the Excel Function: =NORMDIST(z))

= 0.004025

6 0
3 years ago
Select the correct answer.
juin [17]

Answer:

81

Step-by-step explanation:

\sqrt{x}  + 3 = 12 \\  \\  \sqrt{x}  = 12 - 3 \\  \\  \sqrt{x}  = 9 \\  \\  {( \sqrt{x} )}^{2}  =  {(9)}^{2}  \\  \\ x = 81

7 0
2 years ago
IGHT im pretty stupid right now but can you help me out?
matrenka [14]

Answer:

complementary

Step-by-step explanation:

i went to school.

8 0
3 years ago
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