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2 years ago

To multiply two fractions, multiply the numerator by the and the denominator by the

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

3 0

Answer:

numerator, denominator

Step-by-step explanation:

To multiply two fractions, multiply the numerator by the  numerator , and the denominator by the  denominator .

$\dfrac{a}{b}\cdot\dfrac{c}{d}=\dfrac{ac}{bd}$

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What is v? -15V-40 = 23-8V

Andrew [12]

Answer:

V = -9

Step-by-step explanation:

-15V - 40 = 23 - 8V

The objective is to get V alone. To do this, first subtract -15V from both sides. Since -15V is a negative, subtracting it will be adding a positive.

-40 = 23 + 7V

Now that there is only one term with the variable V, subtract 23 from both sides.

-63 = 7V

Finally, divide both sides by 7 to get V completely isolated.

-9 = V.

The final answer is V = -9.

7 0

3 years ago

Read 2 more answers

Which of the following statements is false?

Nutka1998 [239]

A.) All parallelograms are trapezoids

4 0

3 years ago

HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?

tangare [24]

Answer:

$y=-(x-7)(x+3)$

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

$y=-(x+3)(x-7)$ but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is $y=a(x-h)^2+k$ .

This is called vertex form because it gives you the vertex is $(h,k)$ .

We are given that $(h,k)=(2,25)$ which makes our equation:

$y=a(x-2)^2+25$ .

We can find the value of $a$ by plugging in the x-intercept (7,0) for $(x,y)$ into:

$y=a(x-2)^2+25$

$0=a(7-2)^2+25$

$0=a(5)^2+25$

Subtract 25 on both sides:

$-25=a(5)^2$

$-25=a(25)$

Divide both sides by 25:

$\frac{-25}{25}=a$

$-1=a$ .

So the equation for the quadratic is:

$y=-1(x-2)^2+25$

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

$y=-1(x-2)(x-2)+25$

$y=-1(x^2-2x-2x+4)+25$

$y=-1(x^2-4x+4)+25$

$y=-x^2+4x-4+25$

$y=-x^2+4x+21$

Factor out -1:

$y=-(x^2-4x-21)$

WE need to find two numbers that multiply to be -21 and add to be -4:

$y=-(x-7)(x+3)$

8 0

3 years ago

Read 2 more answers

Maura writes an expression equivalent to 8a - (-3 - 5a) - 2a. Her work is in the picture. In what step does Maura make a mistake

NISA [10]

Answer:

11a + 3

Step-by-step explanation:

Step 1 : 8a + 3 - 5a - 2a

error => - 5a

8a - (- 3 - 5a) - 2a =

= 8a + 3 + 5a - 2a

= (8a + 5a - 2a) + 3

= 11a + 3

7 0

3 years ago

Read 2 more answers

12) Domain Range Function? -2

Kisachek [45]

Answer: The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes. (In grammar school, you probably called the domain the replacement set and the range the solution set.

Step-by-step explanation:

7 0

3 years ago