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Mathematics

1 answer:

Reil [10]3 years ago

5 0

where's the question

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The table below represents a function. Which of the following equations could be its function rule? x y 0 0 1 -3 3 -9 -2 6 y = y

alexandr1967 [171]

Answer:

y=-3x

Step-by-step explanation:

6 0

3 years ago

What would the graph of 10x + 7y < 49 look ?

navik [9.2K]

Answer: The graph is attached.

Step-by-step explanation:

1. Solve for y, as following:

$10x+7y$

2. The equation of the line in slope intercept form is:

$y=mx+b$

Where m is the slope and b is the y-intercept.

3. In this case the equation of the line is:

$y=-\frac{10}{7}x+7$

then:

$m=-\frac{10}{7}\\\\b=7$

4. Find the x-intercept. Make y=0. Then:

$0=-\frac{10}{7}x+7\\\frac{10}{7}x=7\\x=4.9$

5. Then, plot the line that passes through the points (0,7) and (4.9, 0).

6. The symbol of the inequality is < therefore, the line must be dashed and indicates that the region under the line must be shaded.

Then you obtain the graph attached.

8 0

3 years ago

Read 2 more answers

PLEASE HELP

lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function $j\left(x\right) \ = \ 4^{x-2}$ , hence the average rate of change (slope of the blue line) between the $x$ and $x+h$ is

$\text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}$

$\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}$