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Snowcat [4.5K]
4 years ago
14

Serena makes $9 per hour cutting lawns. Each day, she earns about $15 in tips. If Serena made no less than $110 on Monday, which

inequality represents h, the number of hours she worked on Monday?
15h+9<110

15h+9>110

9h+15<110

9h+15>110
Mathematics
2 answers:
Elden [556K]4 years ago
4 0
Let h = number of hours she worked on Monday
Given that she makes <span>$9 per hour, it is 9 x h or 9h.
If her tips is a fixed </span><span>$15 amount, then we simply add 15.
9h + 15
This expression above is the amount she made last Monday.
Since she made no less than </span>$110, meaning she made more than <span>$110 last monday.
The final inequality is: 9h + 15 > 110.
</span>
Andrew [12]4 years ago
4 0

Answer:

Let h = number of hours she worked on Monday

Given that she makes $9 per hour, it is 9 x h or 9h.

If her tips is a fixed $15 amount, then we simply add 15.

9h + 15

This expression above is the amount she made last Monday.

Since she made no less than $110, meaning she made more than $110 last monday.

The final inequality is: 9h + 15 > 110.

Step-by-step explanation:

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a

  P(a | e') =  0.22

  P(b | e') =  0.28

  P(c | e') =  0.33

b

  P(a | e' , d' , b') = 0.57

Step-by-step explanation:

From the question we are told that

   The probabilities are

Supplier  chosen            A                     B                    C            

Probability                P(a) = 0.20       P(b) =  0.25   P(c) =  0.15      

                                       D                      E

                                P(d) =  0.30     P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(a | e') =  \frac{P (a \  and \  e')}{P(e')}

      P(a | e') =  \frac{P (a)}{P(e')}

     P(a | e') =  \frac{P (a)}{1- P(e)}

=>   P(a | e') =  \frac{ 0.20}{1- 0.10}

=>   P(a | e') =  0.22

Generally the new probability of companies B  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(b | e') =  \frac{P (b \  and \  e')}{P(e')}

      P(b | e') =  \frac{P (b)}{P(e')}

     P(b | e') =  \frac{P (b)}{1- P(e)}

=>   P(b | e') =  \frac{ 0.25}{1- 0.10}

=>   P(b | e') =  0.28

Generally the new probability of companies C  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(c | e') =  \frac{P (c \  and \  e')}{P(e')}

      P(c | e') =  \frac{P (c)}{P(e')}

     P(c | e') =  \frac{P (c)}{1- P(e)}

=>   P(c | e') =  \frac{ 0.15}{1- 0.10}

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Generally the new probability of companies D  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(d | e') =  \frac{P (d \  and \  e')}{P(e')}

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=>       P(N) =  1 - [0.10 +0.25  +0.30 ]

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      P(a | e' , d' , b') =  \frac{P(a)}{P(N)}

=>     P(a | e' , d' , b') =  \frac{0.20 }{0.35 }    

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(-4a^3 b^2)^2 × (3a^2 b)

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3 years ago
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