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Marina CMI [18]
2 years ago
11

Please help me with my math! Read the instructions and tell me what to do for that assignment cus I don't understand this lesson

! And give an answer for at least one of them!

Mathematics
2 answers:
prisoha [69]2 years ago
5 0
1. 155
2. 222
3. 44
4. 132
5. 163

I don’t know the last one sorry :)
saul85 [17]2 years ago
4 0

Answer: You should be using the Long Division Method for these problems.

Step-by-step explanation:

You have to find the Remainder for these math questions, keep in mind some of these Quotients (Division) don't always have a remainder.

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Find the value of x<br> classify the triangle
makvit [3.9K]

Step-by-step explanation:

Value of x=180-(44+45)=91degrees.

The triangle is a right scalene.

PLEASE MARK MY ANSWER AS BRAINILIEST AND FOLLOW ME.

4 0
3 years ago
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Please help ASAP will mark brainliest
Katena32 [7]

Answer:

Solution is m>15

Explanation:

(-4/5)m<-12

<=> (4/5)m>12

<=> m>12*5/4

<=> m>60/4

<=>m>15

6 0
3 years ago
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HELP LOL! IS THIS PROPORTIONAL EASY POINTS
goblinko [34]

Answer:

nonproportional

Step-by-step explanation:

nonproportional is what i think

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3 years ago
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In △ABC AL is an angle bisector (L∈ BC ). Point M∈ AB so that LM=AM=BM. Find the angles in △ABC, if AC=2AL.
Diano4ka-milaya [45]

If AM=BM, then point M is a middle point of side AB.

1. Consider triangle AML. You know that AM=ML, then this triangle is isosceles and AL is its base. The angles adjacent to the base of isosceles triangle are conruent, this means that \angle MAK\cong \angle AML.

2. Consider lines ML and AC. The angle bisector AL is transversal. Since alternate interior angles \angle MAK\cong \angle AML, you have that lines ML and AC are parallel. This means that ML is a middle line of triangle and 2ML=AC. Also you know that AC=2AL. This gives you that ML=AL. Now ML=AL and ML=AM gives you that triangle AML is equilateral.

3. In equilateral triangle AML all angles are congruent and have measures 60°. Thus, m∠AML=m∠MLA=m∠LAM=60°.

4. AL is angle bisector, then m∠MAL=m∠LAC=60° and m∠BAC=m∠MAL+m∠LAC=120°.

5. Consider ΔBML, it is isosceles, because BM=ML and m∠BML=180°-m∠AML=180°-60°=120°. Then,

m\angle MBL=m\angle MLB=\dfrac{180^{\circ}-120^{\circ}}{2}=30^{\circ}.

6. Consider triangle ABC. In this triangle m∠A=120°, m∠B=30°, then

m∠C=180°-m∠A-m∠B=180°-120°-30°=30°.

Answer: m∠A=120°, m∠B=m∠C=30°.

3 0
3 years ago
Which of the following equations have complex roots?
goldenfox [79]

9514 1404 393

Answer:

  B.  3x² +2 = 0

Step-by-step explanation:

The equation of A has a couple of real roots. We're pretty sure there are complex numbers that will satisfy this equation, but we don't know how to find them. (We suspect a typo, and that the equation is supposed to be 2x² +1 = 7x, which has only real roots.)

__

The equation of B can be rewritten as ...

  x² = -2/3

This will have complex roots.

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The discriminants of both equations C and D are positive, so those have only real roots.

  2x² -5x -1   ⇒   d = (-5)² -4(2)(-1) = 33

  3x² -6x -1   ⇒   d = (-6)² -4(3)(-1) = 48

6 0
3 years ago
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