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olga55 [171]
2 years ago
15

Simplify and evaluate without a calculator. 3*(m-4)-n*(m-4) if m=5 and n=3

Mathematics
2 answers:
il63 [147K]2 years ago
8 0

Answer:

Step-by-step explanation:

If m = 5 and n = 3, then

3*(m-4)-n*(m-4) becomes 3*(5 - 4) - 3(5 - 4), or 3(1) - 3(1) = 0

Another way to do this would be to factor out m - 4 first.  We get:

(m - 4)(3 - n), and substituting the given values for m and n results in

5(3 - 3) = 0 (as before).

Katarina [22]2 years ago
6 0

Answer:

0

Step-by-step explanation:

3*(m-4)-n*(m-4)   m = 5, n = 3

3*(5-4)-3*(5-4)

3*(1)-3*(1)

3-3

0

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Find the slope of the line with x intercept 9 and y intercept of -2
elena-s [515]

Answer:

2/9

Step-by-step explanation:

Find the slope of the line with x intercept 9 and y intercept of -2

Given that the equation of the line is y = mx+b

x intercept occurs when y = 0

The coordinate of x intercept is (9,0)

y intercept occurs at x = 0

The coordinate of y intercept is (0, -2)

Slope m = y2-y1/x2-x1

m = -2-0/0-9

m = -2/-9

m = 2/9

Hence the required slope is 2/9

8 0
3 years ago
Which statement must be true about line TU?
just olya [345]
Line tu is parallel to rs
5 0
3 years ago
Read 2 more answers
How would I set up this problem?
Sliva [168]
Since in 1990 there are 28%, we need to figure out when it gets to 31%. In addition, since it increases by 0.6% every year, we can say that 0.6x+28 (since 28 is the base value) is the percentage of babies born in wedlock every year. Therefore, to get 0.6x+28=31, we subtract 28 from both sides to get 0.6x=3
Dividing both sides by 0.6, we get x=5=the amount of years it takes to get 31% of babies born in wedlock. Since 1990 is the base value (we start from there!), we add 5 to that to get 1990+5=1995 as the yar
4 0
3 years ago
Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0
3 years ago
Neverminded solved thanks for veiwing anyways.
docker41 [41]

Answer:

•________________•♡♡

4 0
3 years ago
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