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olga55 [171]
2 years ago
15

Simplify and evaluate without a calculator. 3*(m-4)-n*(m-4) if m=5 and n=3

Mathematics
2 answers:
il63 [147K]2 years ago
8 0

Answer:

Step-by-step explanation:

If m = 5 and n = 3, then

3*(m-4)-n*(m-4) becomes 3*(5 - 4) - 3(5 - 4), or 3(1) - 3(1) = 0

Another way to do this would be to factor out m - 4 first.  We get:

(m - 4)(3 - n), and substituting the given values for m and n results in

5(3 - 3) = 0 (as before).

Katarina [22]2 years ago
6 0

Answer:

0

Step-by-step explanation:

3*(m-4)-n*(m-4)   m = 5, n = 3

3*(5-4)-3*(5-4)

3*(1)-3*(1)

3-3

0

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A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s
mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, \theta=25°

Initial speed is, u=15\ m/s

Time of flight is, t=3.0\ s

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = -h (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, g=-9.8\ m/s^2

Now, using the following equation of motion;

-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, v_y=0\ m/s

Now, using the following equation of motion, we have:

v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m

Therefore, the maximum height of the brick is 2.05 m.

5 0
3 years ago
What is the value of "c" in the following quadratic? (Make sure the equation is in
garri49 [273]

               \rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}

           <em>What is the value of c in the quadratic </em>\large\text{$x^2+28=-11x$}?

          \rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

           Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding \large\textit{11x} on both sides:-

\large\text{$x^2+28-11x=0$}

We can switch the order of 28 and -11x:-

\large\text{$x^2-11x+28=0$}

  Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

  •  \large\text{$ax^2+bx+c=0$}

Now we can just write our <u>quadratic</u> here:-

  • \large\text{$x^2-11x+28=0$}

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

   

Henceforth, we conclude that the value of "c" in the given quadratic is:-

 \Large\textbf{28}\Large\checkmark

<h3>         Good luck with your studies.</h3>

        \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}    

5 0
2 years ago
A 128 inch board is cut into 3 pieces. The second piece is 33 inches longer than the first piece, and the third is three times a
LenaWriter [7]

Answer:

The first piece is 19 inches, the second is 52, and the third piece is 57.

Step-by-step explanation:

Solve for x using (x) + (x + 33) + (3x) = 128.

3 0
3 years ago
Please help me number 1
xenn [34]

Answer:

47 degrees

Step-by-step explanation:

You have a straight line, which has an angle measure of 180 degrees.

180-133=47

Your answer can come from the line with 133 on it because the two lines are parallel with a transversal line. Because the two lines are parallel, they have the same interior angle measurements.

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diamong [38]

Answer:

A   The engine is powered by steam, which is created when wood burned in the furnace heats water in the boiler turns it to steam

Step-by-step explanation:

I took the quiz

7 0
3 years ago
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