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mestny [16]
3 years ago
15

How would I set up this problem?

Mathematics
1 answer:
Sliva [168]3 years ago
4 0
Since in 1990 there are 28%, we need to figure out when it gets to 31%. In addition, since it increases by 0.6% every year, we can say that 0.6x+28 (since 28 is the base value) is the percentage of babies born in wedlock every year. Therefore, to get 0.6x+28=31, we subtract 28 from both sides to get 0.6x=3
Dividing both sides by 0.6, we get x=5=the amount of years it takes to get 31% of babies born in wedlock. Since 1990 is the base value (we start from there!), we add 5 to that to get 1990+5=1995 as the yar
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Find the value of the derivative (if it exists) at the indicated extremum. (If an answer does not exist, enter DNE.)
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Answer:

The answer is "0".

Step-by-step explanation:

Please find the correct question in the attached file.

Given value:

\to f(x) =\frac{x^2}{x^2+5}\\\\

Formula:

\bold{\frac{d}{dx} \frac{u}{v} = \frac{ v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}}

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