What is an equation for the line that passes through the points (-2, 3) and (2, 1)?
1 answer:
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Answer:
OPTION A
Step-by-step explanation:
To find the table substitute the points on the given function and compare the values.
The given function is: .
OPTION A:
(i) When x = -2
LHS = y = 6.
RHS = (-2)² + 2 = 4 + 2 = 6.
LHS = RHS
(ii) When x = -1
LHS = y = 3
RHS = (-1)² + 2 = 1 + 2 = 3.
LHS = RHS
(iii) When x = 0
LHS = y = 2
RHS = 0² + 2 = 2.
LHS = RHS
(iv) When x = 1
LHS = y = 3
RHS = (1)² + 2 = 1 + 2 = 3.
LHS = RHS
(v) When x = 2
LHS = y = 6
RHS = (2)² + 2 = 4 + 2 = 6
LHS = RHS
OPTION B:
(i) When x = -2
LHS = y = -2
RHS = (-2)² + 2 = 6
LHS RHS
OPTION B is eliminated.
OPTION C:
(i) When x = -2
Using the same reason as OPTION B this option is eliminated as well.
So, OPTION A is the correct answer.
So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>
So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:
Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now we can rewrite this expression as<u> , which is your final answer.</u>