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kirill [66]
2 years ago
7

Find the least common multiple of 8y^2 and 7m

Mathematics
1 answer:
Flura [38]2 years ago
4 0

Answer:   56y^2m

which is the same as writing 56y^2m

====================================================

Explanation:

Let's focus on the coefficients 8 and 7 for now.

To find the LCM of those values, list out the multiples. Circle the smallest number that can be found in both sets at the same time.

  • multiples of 8 are: 8, 16, 24, 32, 40, 48, 56, 64, ...
  • multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56, 63, ....

We see that 56 is the LCM of 7 and 8.

Or you could use this shortcut

LCM = (x*y)/GCF

where x and y are the two numbers. The mention of "GCF" refers to the GCF of x and y. In this case, the GCF is 1 so,

LCM = (x*y)/GCF = (8*7)/1 = 8*7 = 56.

----------------------

Once we determine that, we look at the variable terms now.

The y^2 and m will be tacked onto the 56 to arrive at the final answer 56y^2m

This is because y and m are the unique variables, and we go for the highest exponent of each. It's similar to the LCM formula used earlier.

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