Subtract 2 from both sides.
Your equation will be: 4x+3=x
Subtract 4x from both sides.
Yoir equation will be: 3= -3x
Divide by -3x on both sides.
Your final answer: x=-1
Find the least common multiple of 8y^2 and 7m
1 answer:
Answer:
which is the same as writing 56y^2m
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Explanation:
Let's focus on the coefficients 8 and 7 for now.
To find the LCM of those values, list out the multiples. Circle the smallest number that can be found in both sets at the same time.
- multiples of 8 are: 8, 16, 24, 32, 40, 48, 56, 64, ...
- multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56, 63, ....
We see that 56 is the LCM of 7 and 8.
Or you could use this shortcut
LCM = (x*y)/GCF
where x and y are the two numbers. The mention of "GCF" refers to the GCF of x and y. In this case, the GCF is 1 so,
LCM = (x*y)/GCF = (8*7)/1 = 8*7 = 56.
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Once we determine that, we look at the variable terms now.
The y^2 and m will be tacked onto the 56 to arrive at the final answer 56y^2m
This is because y and m are the unique variables, and we go for the highest exponent of each. It's similar to the LCM formula used earlier.
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Subtract 2 from both sides.
Your equation will be: 4x+3=x
Subtract 4x from both sides.
Yoir equation will be: 3= -3x
Divide by -3x on both sides.
Your final answer: x=-1
Answer:
2.87%
Step-by-step explanation:
We have the following information:
mean (m) = 200
standard deviation (sd) = 50
sample size = n = 40
the probability that their mean is above 21.5 is determined as follows:
P (x> 21.5) = P [(x - m) / (sd / n ^ (1/2))> (21.5 - 200) / (50/40 ^ (1/2))]
P (x> 21.5) = P (z> -22.57)
this value is very strange, therefore I suggest that it is not 21.5 but 215, therefore it would be:
P (x> 215) = P [(x - m) / (sd / n ^ (1/2))> (215 - 200) / (50/40 ^ (1/2))]
P (x> 215) = P (z> 1.897)
P (x> 215) = 1 - P (z <1.897)
We look for this value in the attached table of z and we have to:
P (x> 215) = 1 - 0.9713 (attached table)
P (x> 215) =.0287
Therefore the probability is approximately 2.87%
