Find the least common multiple of 8y^2 and 7m
1 answer:
Answer:
which is the same as writing 56y^2m
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Explanation:
Let's focus on the coefficients 8 and 7 for now.
To find the LCM of those values, list out the multiples. Circle the smallest number that can be found in both sets at the same time.
- multiples of 8 are: 8, 16, 24, 32, 40, 48, 56, 64, ...
- multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56, 63, ....
We see that 56 is the LCM of 7 and 8.
Or you could use this shortcut
LCM = (x*y)/GCF
where x and y are the two numbers. The mention of "GCF" refers to the GCF of x and y. In this case, the GCF is 1 so,
LCM = (x*y)/GCF = (8*7)/1 = 8*7 = 56.
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Once we determine that, we look at the variable terms now.
The y^2 and m will be tacked onto the 56 to arrive at the final answer 56y^2m
This is because y and m are the unique variables, and we go for the highest exponent of each. It's similar to the LCM formula used earlier.
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The explicit rule for given sequence is:
Further explanation:
We have to determine first of all if the sequence is arithmetic or geometric.
- If the difference of two consecutive terms is same then the sequence is arithmetic sequence
- If the ratio of two consecutive terms is same then the sequence is geometric sequence
Given sequence is:
12,22,32,42
The common difference is 10 which is same for all consecutive terms. So the sequence is an arithmetic sequence.
The general formula for arithmetic sequence is:
Putting the values of a1 and d
The explicit rule for given sequence is:
Keywords: Arithmetic sequence, Common Difference
Learn more about arithmetic sequence at:
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