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natulia [17]
2 years ago
8

Karen's mom is filling 12 birthday hats with candy for her birthday party. Each hat is shaped like a cone with a height of 6 inc

hes and a radius of 3 inches.
Which statements are true? Choose all that are correct.
Mathematics
1 answer:
KatRina [158]2 years ago
6 0

The volume of each birthday hat is 56.55 in³ and the 12 hats has a total volume of 678.58 in³

<h3>What is volume?</h3>

Volume is the amount of space occupied by a three dimensional shape or object.

The volume of a cone is given by:

volume = (1/3) * π * radius² * height

The cone that has a height of 6 inches and a radius of 3 inches. Hence:

Volume = (1/3) * π * 3² * 6 = 56.55 in³

For 12 hats:

Volume = 12 *  56.55 in³ = 678.58 in³

The volume of each birthday hat is 56.55 in³ and the 12 hats has a total volume of 678.58 in³

Find out more on volume at: brainly.com/question/12410983

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SOMEONE HELP BECAUSE I DONT GET THIS
Leno4ka [110]

Answer:

x = 18

m<A = 166°

Step-by-step explanation:

The parallel lines are cut by a transversal, so corresponding angles A and B are congruent.

7x + 40 = 3x + 112

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x = 18

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Yes

Step-by-step explanation:

Multiply one eqution so that they are same.

For example:

2x+17y+48=0

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What is the simplified expression for the perimeter of the polygon?
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Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}

Now, create a common denominator. To do this, we can multiply the first term by (<em>a</em> + 1) and the second term by (<em>a</em> + 2). Hence:

\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}

Add the fractions:

\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}

Factor:

\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}

Simplify:

\displaystyle =\frac{a+4}{(a-1)(a+1)}

We can expand. Therefore:

\displaystyle =\frac{a+4}{a^2-1}

Problem 2)

We want to simplify:

\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}

Again, let's create a common denominator. First, let's factor out a negative from the second term:

\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}

Now to create a common denominator, we can multiply the first term by (<em>a</em> - <em>c</em>) and the second term by (<em>a</em> - <em>b</em>). Hence:

\displaystyle =\frac{(a-c)}{(a-b)(b-c)(a-c)}-\frac{(a-b)}{(a-b)(b-c)(a-c)}

Subtract the fractions:

\displaystyle =\frac{(a-c)-(a-b)}{(a-b)(b-c)(a-c)}

Distribute and simplify:

\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}

Cancel. Hence:

\displaystyle =\frac{1}{(a-b)(a-c)}

4 0
3 years ago
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