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Snezhnost [94]
3 years ago
12

PLEASE DO NOT BE NONSENSE​

Mathematics
2 answers:
algol133 years ago
7 0

Answer:

7. 4- 4.5

8. 2- 4

9. 3- round 4 .94 then multiply by 7

10. 4-. 11.58

<h3>hope it helps (^^)</h3>

<h3># Cary on learning</h3>
gayaneshka [121]3 years ago
6 0
7. 18.3 divided by 4 is 4.575. 4.575 is closest to 4.5 which would be our answer

8. 14.6 divided by 3 is 4.86. If we round it, then it would be 5 which would be the answer

10. The answer to the problem would be 11.58
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2. Ronnie buys 18 identical t-shirts costing £36. How much would 1 t-shirt cost? <br>​
fgiga [73]
36/18=2
Each shirt is £2
4 0
3 years ago
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which expression can be used to determine the slope of the line that passes though the points (-7, 3) and (1, -9)?
Zolol [24]

Answer:

-3/3    x -15/2

Step-by-step explanation:

hope this helps

5 0
3 years ago
What is 9.39 to one decimal place
mafiozo [28]
9.4 because the number after the firs decimal point is higher than 5
5 0
3 years ago
a fair coin is flipped 10 times. what is the probability of getting the same number of heads and tails
Dafna11 [192]

If you flip a coin one time, the probability to get a Head is

p = 1/2

The probability of not getting a head in a single toss is :

q = 1 - 1/2 = 1/2

Thus there is only one unique situation to get the same number of heads and tails : in 10 toss you need to get exactly five heads, it will means that the rest is the tails.

Now using Binomial theorem of probability, the probability of getting exactly x = 5 heads in a total of n = 10 tosses is :

P(X = 5) = \frac{10!}{5!*5!} *(\frac{1}{2})^{5} *(\frac{1}{2})^{5}≈ 0.246

So the probability of that is 24,6 %

Good Luck

3 0
2 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
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