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3 years ago

Simplify 4w^5(-9w^3-9w-9) please help!

Mathematics

2 answers:

Elis [28]3 years ago

6 0

Answer:

- 36 $w^{8}$ - 36 $w^{6}$ - 36 $w^{5}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , then

4 $w^{5}$ (- 9w³ - 9w - 9) ← distribute parenthesis by 4 $w^{5}$

= - 36 $w^{(5+3)}$ - 36 $w^{(5+1)}$ - 36 $w^{5}$

= - 36 $w^{8}$ - 36 $w^{6}$ - 36 $w^{5}$

vekshin13 years ago

5 0

Answer:

$= > 4 {w}^{5} ( - 9 {w}^{3} - 9w - 9) \\ \: \: \: \: = > - 36w {}^{5 + 3} - 36 {}^{5 + 1} - 36 {}^{5} \\ = > - 36 w{}^{8} - {36w}^{6} - 36w {}^{5}$

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Two identical rubber balls are dropped from different heights. Ball 1 is dropped from a height of 196 feet, and ball 2 is droppe

Anon25 [30]

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5 0

3 years ago

Drag the expressions into the boxes to correctly complete the table.

lora16 [44]

Answer:

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form $ax^n$ .

Here:

$n$ = non-negative integer

$a$ = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

$x^4+\frac{5}{x^3}-\sqrt{x}+8$

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains $\sqrt{x}$ , so it is not a polynomial.

Also it contains the term $\frac{5}{x^3}$ which can be written as $5x^{-3}$ , meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression $x^4+\frac{5}{x^3}-\sqrt{x}+8$ is not a polynomial.

Given the expression

$-x^5+7x-\frac{1}{2}x^2+9$

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

$\left|x\right|^2+4\sqrt{x}-2$

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

$x^3-4x-3$

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

$\frac{4}{x^2-4x+3}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

3 0

3 years ago

abrl,belle and cindy have $408 altogeter.belle has $7 more than cindy and $5 more than abel.how much does abel have?

faltersainse [42]

ABC = 408
C + 7 = B
A + 5 = B

B - 7 + B - 5 + B = 408
3B - 12 = 408
+ 12 = +12
3B = 420
/3 = /3
B = 120
A = 115
C = 113
The answer is A = 115, Abel has $ 115

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3 years ago

Please help me, I don't understand this!

Montano1993 [528]

whats the question?

3 0

3 years ago

Read 2 more answers

Five more than three times a number is 197. find the mlnumber

insens350 [35]

Answer:

Step-by-step explanation:

If the number is x we have the equation:-

3x + 5 = 197

Subtract 5 from both sides:-

3x = 192

x = 192/3

x = 64

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3 years ago