if you solve those equations for "c" and "d" respectively, you'd get, well the Q point of c,d
Since there is a power of 2 and constants, without a variable power of 1, I would use square root method.
Move the 7 to the right and you get 2x^2 = 16
Then divide both sides by 2 and get x^2 = 8
Now take the square root of each side and get x = +-sqrt 8
sqrt 8 can be simplified since 2*4 = 8 and 4 is a perfect square.
Therefore the final answer is x = +-2sqrt2
Answer: 4th sequence is closest to the theoretical probability of drawing a king or queen.
Step-by-step explanation:
Since we have know that there are 4 queens and 4 kings in the regular pack .
Total number of cards = 52
So, probability of getting king or queen is given by
1)5 6 8 2 Q 4 8 3 2 A 2 3 10 J J 4 A 5 3 8
So, probability of getting king or queen is given by
2)K J 5 8 4 3 6 Q 9 J Q 2 8 Q 9 2 Q A 7 K
So, probability of getting king or queen is given by
3)3 8 3 2 7 4 J A 6 3 2 A A 6 3 8 6 10 5 4
So, probability of getting king or queen is given by
0 as there is no queen as well as king.
4)4 8 6 K J 7 Q 3 A K 2 5 8 9 10 2 4 A 6 7
So, probability of getting king or queen is given by
Hence, 4th sequence is closest to the theoretical probability of drawing a king or queen.
It's 8x + 16y/2 + 4x - 4y :))