Answer:
Step-by-step explanation:
Answer:
J=12
Step-by-step explanation:
(2/3)*j = 8 // - 8
(2/3)*j-8 = 0
2/3*j-8 = 0 // + 8
2/3*j = 8 // : 2/3
j = 8/2/3
j = 12
<h3>1.</h3>
The picture shows 5 groups of 3 bars. Each bar represents 1/10. We take the picture to mean that ...
... (15/10) / 5 = 3/10
In decimal:
... 1.5 / 5 = 0.3
<h3>2.</h3>
The picture shows 3 groups of 2 bars. Each bar represents 1/10. We take the picture to mean that ...
... (6/10) / 3 = 2/10
In decimal:
... 0.6 / 3 = 0.2
<h3>3.</h3>
The picture shows 4 groups, each consisting of 1 large square, 1 bar, and 4 small squares. We take the picture to mean that ...
... (4 + 4/10 + 16/100) / 4 = 1 + 1/10 + 4/100
In decimal:
... 4.56 / 4 = 1.14
Please note that 16/100 is equivalent to 1/10 + 6/100. In order to do the division, one of the 1/10 bars needed to be changed into 10 small squares, 10/100.
<h3>4.</h3>
The picture shows 3 groups, each consisting of 1 large square, 3 bars, and 2 small squares. We take the picture to mean that ...
... (3 + 9/10 +6/100) / 3 = 1 +3/10 + 2/100
In decimal:
... 3.96 / 3 = 1.32
Answer:
+120/169 or -120/169
Step-by-step explanation:
- let
![cos^{-1}[\frac{5}{13} ] = \alpha](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%5B%5Cfrac%7B5%7D%7B13%7D%20%20%5D%20%3D%20%5Calpha)
where, alpha is some angle that satisfies the assumed condition.
- so,
[ taking cos to the other side or applying cos on both sides]
- now, substitute this in the given expression
as sin
= 
[by general trigonometry formula: ![cos^{2}[\beta] +sin^{2}[\beta]=1](https://tex.z-dn.net/?f=cos%5E%7B2%7D%5B%5Cbeta%5D%20%20%2Bsin%5E%7B2%7D%5B%5Cbeta%5D%3D1)
]
so if , we can get sin
from the above formula as + or - 12/13
(because, after taking square root on both sides we keep + or -]
- as, sin
![2\beta = 2*sin[\beta ]*cos[\beta ]](https://tex.z-dn.net/?f=2%5Cbeta%20%20%3D%202%2Asin%5B%5Cbeta%20%5D%2Acos%5B%5Cbeta%20%5D)
[by general trigonometry formula]
- here, now
![sin[2\alpha ]=2*(+or- 12/13)*5/13\\](https://tex.z-dn.net/?f=sin%5B2%5Calpha%20%5D%3D2%2A%28%2Bor-%2012%2F13%29%2A5%2F13%5C%5C)
so, the final value can be 120/169 or -120/169.
Answer:
Gabby received
7 nickels
10 dimes
3 quarters
Step-by-step explanation:
Let
x----> the number of dimes
y----> the number of nickels
z---> the number of quarters
Remember that
1 dime=$0.10
1 nickel=$0.05
1 quarter=$0.25
we know that
0.10x+0.05y+0.25z=2.10 ------> equation A
x=y+3-----> equation B
z=y-4 -----> equation C
substitute equation B and equation C in equation A and solve for y
0.10(y+3)+0.05y+0.25(y-4)=2.10
0.10y+0.30+0.05y+0.25y-1=2.10
0.40y=2.10-0.30+1
0.40y=2.80
y=7 nickels
<em>Find the value of x</em>
x=y+3 -----> x=7+3=10 dimes
<em>Find the value of z</em>
z=y-4 -----> z=7-4=3 quarters
therefore
Gabby received
7 nickels
10 dimes
3 quarters
