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otez555 [7]
3 years ago
13

Simplify. −7i⋅(−8i) −56 −56i 56i 56

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0
Your answer is A. -56
Hope this helps!
matrenka [14]3 years ago
8 0
A. -56

This should be your correct answer!

Hope this helps!
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Please help me i need to reconcile but it is hard, thank you
Elina [12.6K]

Answer:

Step-by-step explanation:

Add the first two columns - third column. See if it equals last column.

Number one is correct, number 2 is off by $1.00,etc

let me know if you are still confused

5 0
3 years ago
What is the area of the shaded section?
Ray Of Light [21]

Answer:

270cm squared

area of shaded part rectangle is 180

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3 years ago
Find the area of a rectangle that has a length of 4/5 of a meter and a width of 3/5
Helen [10]

Answer:

Step-by-step explanation:

Givens

L = 4/5 m

w = 3/5 m

Formula

A = L * w

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6 0
2 years ago
What is the solution set for the inequality 2x-3> 5x+6?
prisoha [69]

3x <  - 9 \\ x <  - 3
4 0
3 years ago
Jane had 27 stickers two weeks ago. She was buying stickers each day for those two weeks. She bought 3 stickers two weeks ago, a
xeze [42]

Answer:

<u>At Present Jane has Total Stickers = 251</u>

Step-by-step explanation:

Stickers Initially = 27

Jane bought stickers on 1st day = 3

Remaining days = 13

Each next day she bought 2 more stickers than the previous day, so:

Stickers bought in the last 2 weeks (14 days) = n+(n+2)+(n+2+2)+(n+2+2+2)+.............+(n+2(13))

here n =3

So:

Stickers bought in the last 2 weeks (14 days) = 3+5+7+9+11+13+15+17+19+21+23+25+27+29

Stickers bought in the last 2 weeks (14 days) = 224

At Present Jane has Total Stickers = Stickers Initially+ Stickers bought in the last 2 weeks (14 days)

At Present Jane has Total Stickers = 27+224

<u><em>At Present Jane has Total Stickers = 251</em></u>

6 0
3 years ago
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