End of First Year (750/100)x12(3/5)=54 $750+54=804
End of Second Year (804/100)x12(3/5) = 58 $804+58=862
End Of Third Year (862/100)x12(3/5) = 62 $862+62=924
STOCK WORTH NOW = 924
Answer:
c
Step-by-step explanation:
9514 1404 393
Answer:
- Josh: 32 mph, 64 mi
- Greg: 64 mph, 320 mi
Step-by-step explanation:
Let x represent Josh's rate of travel in miles per hour. After 2 hours, his distance is ...
distance = speed · time
distance = x · 2 = 2x
Then 2x is Greg's rate of travel After 5 hours, his distance is ...
distance = speed · time
distance = (2x) · 5 = 10x
The distance they are apart is ...
10x -2x = 256
8x = 256
x = 32
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Josh's rate: 32 miles per hour; Josh's distance = (2 h)(32 mi/h) = 64 miles.
Greg's rate: (32 mi/h)·2 = 64 mi/h; Greg's distance = (5 h)(64 mi/h) = 320 miles.
<em>__</em>
<em>Check</em>: 320 miles - 64 miles = 256 miles . . . . correct separation
Just try to follow my description. When two persons are in the cabin, there is only 1 handshake. When a third person comes, he will have to handshake the two people who came before him. So, there will be 2 handshakes. When a fourth person comes, he would make 3 handshakes with the 3 people who came before him. When the fifth person comes, he would make 4 handshakes with the 4 people who came before him. So, you see there is a pattern. The number of handshakes is 1 less than the total number of people inside the cabin. So, if there are 14 people in the cabin, the last person to come in would have to make 13 handshakes with the 13 people who came in first. Obtaining the sum of all the handshakes starting from the 2 handshakes initially to the 13 handshakes, the sum would be
Total handshakes = 2+3+4+5+6+7+8+9+10+11+12+13
Total handshakes = 90
Therefore, there will be a total of 90 handshakes made within the cabin of 14 people.
