Answer:
2 3/5
Step-by-step explanation:
13/5
5 goes into 13 2 time
2*5 =10
13-10 =3
There is 3 left over. This goes over the denominator
2 3/5
For this case we have the following equations:
![f (x) = \frac {1} {x}\\g (x) = x ^ 2-3x](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%5Cfrac%20%7B1%7D%20%7Bx%7D%5C%5Cg%20%28x%29%20%3D%20x%20%5E%202-3x)
We must find ![(f_ {o} g) (x):](https://tex.z-dn.net/?f=%28f_%20%7Bo%7D%20g%29%20%28x%29%3A)
By definition of composition of functions we have to:
![(f_ {o} g) (x) = f (g (x))](https://tex.z-dn.net/?f=%28f_%20%7Bo%7D%20g%29%20%28x%29%20%3D%20f%20%28g%20%28x%29%29)
So:
![(f_ {o} g) (x) = \frac {1} {x ^ 2-3x}](https://tex.z-dn.net/?f=%28f_%20%7Bo%7D%20g%29%20%28x%29%20%3D%20%5Cfrac%20%7B1%7D%20%7Bx%20%5E%202-3x%7D)
We must find the domain of f (g (x)). The domain will be given by the values for which the function is defined, that is, when the denominator is nonzero.
![x ^ 2-3x = 0\\x (x-3) = 0](https://tex.z-dn.net/?f=x%20%5E%202-3x%20%3D%200%5C%5Cx%20%28x-3%29%20%3D%200)
So, the roots are:
![x_ {1} = 0\\x_ {2} = 3](https://tex.z-dn.net/?f=x_%20%7B1%7D%20%3D%200%5C%5Cx_%20%7B2%7D%20%3D%203)
The domain is given by all real numbers except 0 and 3.
Answer:
x other than 0 and 3
I got the factors of 40 but both numbers do not add up to 11. Negative numbers are not considered because the product and sum are positive numbers.
1 x 40 = 40 1 + 40 = 41
2 x 20 = 40 2 + 20 = 22
4 x 10 = 40 4 + 10 = 14
5 x 8 = 40 5 + 8 = 13
I also got the addends of 11 and solved each set to get the product
1 + 10 = 11 1 x 10 = 10
2 + 9 = 11 2 x 9 = 18
3 + 8 = 11 3 x 8 = 24
4 + 7 = 11 4 x 7 = 28
5 + 6 = 11 5 x 6 = 30
I think answer is b that is 10raise to 2
Learned this yesterday, lol.
It's basically just:
100[ (33-24)/24 ]
100[ 9/24 ]
100[ 0.375 ]
37.5%