Question

Find the 62nd term of the arithmetic sequence 15, 13, 11, ...

Answer 1

Answer:

$a_{62}=-107$

Step-by-step explanation:

This is an arithmetic sequence:

$a_n=a_1+(n-1)d$

where d is the common difference and n is the index of any given term.

The common difference of the given sequence is -2:

$13-15=-2\\11-13=-2$

Using the first term and the common difference, you can write the equation for this sequence:

$a_n=15+(n-1)(-2)$

And using that equation, you can find the 62nd term:

$a_{62}=15+(62-1)(-2)\\a_{62}=15+(61)(-2)\\a_{62}=15-122\\a_{62}=-107$