Answer:
Approximately 104 joggers are female
Step-by-step explanation:
The U.S census bureau reported that 9 out of every 20 joggers at female.
Let x be the number of females out of 230 joggers.
Rewrite it as

Now we can write a proportion:

Cross multiply:
![20x=9\cdot 230\\ \\2x=9\cdot 23\ [\text{Divided by 10}]\\ \\x=\dfrac{9\cdot 23}{2}=\dfrac{207}{2}=103.5\approx 104](https://tex.z-dn.net/?f=20x%3D9%5Ccdot%20230%5C%5C%20%5C%5C2x%3D9%5Ccdot%2023%5C%20%5B%5Ctext%7BDivided%20by%2010%7D%5D%5C%5C%20%5C%5Cx%3D%5Cdfrac%7B9%5Ccdot%2023%7D%7B2%7D%3D%5Cdfrac%7B207%7D%7B2%7D%3D103.5%5Capprox%20104)
F+s=95
f=s+27
s+27+s=95
2s=95-27
sixth graders = 34
fith graders = 61
Answer:
x=<u>1</u>
2
hope it helps
Step-by-step explanation:
–1
x=0.5,x=2
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
<em />
As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,