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Tcecarenko [31]
3 years ago
6

What do I do I can't understand it my teacher stupid

Mathematics
1 answer:
denpristay [2]3 years ago
5 0
Make them all fractions over 4, so 3 would be 12/4, and 1 1/4 would be 5/4 so add them together 
12/4+5/4= 17/4 then divide by 4 to reduce it, to get 4 1/4
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The U.S census bureau reported that 9 out of every 20 joggers at female. On a trail there were 230 joggers on July 4. Approximat
hodyreva [135]

Answer:

Approximately 104 joggers are female

Step-by-step explanation:

The U.S census bureau reported that 9 out of every 20 joggers at female.

Let x be the number of females out of 230 joggers.

Rewrite it as

\begin{array}{cc}\text{Female}&\text{All joggers}\\9&20\\x&230\end{array}

Now we can write a proportion:

\dfrac{9}{x}=\dfrac{20}{230}

Cross multiply:

20x=9\cdot 230\\ \\2x=9\cdot 23\ [\text{Divided by 10}]\\ \\x=\dfrac{9\cdot 23}{2}=\dfrac{207}{2}=103.5\approx 104

7 0
3 years ago
I need help - Geometry - 15 points + brainlyist - 1 question -
lara [203]

Answer:

120 = (15 + 22)x + 4 + 5 \\ 120 - 9 = 37x \\ 111 = 37x \\ x = 111 \div 37 = 3 \\

15x + 5 = 3 \times 15 + 5 = 50

8 0
3 years ago
Read 2 more answers
And the 95 fifth and sixth graders going on a field trip there are 27 more fifth-graders than six graders how many fifth-graders
Alborosie
F+s=95
f=s+27
s+27+s=95
2s=95-27
sixth graders = 34
fith graders = 61
6 0
4 years ago
Read 2 more answers
Y = -2x - 1; (2,-1)<br> Slope intercept form
zlopas [31]

Answer:

x=<u>1</u>

2

hope it helps

Step-by-step explanation:

–1

x=0.5,x=2

8 0
3 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
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