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Roman55 [17]
2 years ago
12

Please help me with this please and thank you

Mathematics
1 answer:
Alina [70]2 years ago
3 0

Step-by-step explanation:

y = ax^n + bx^(n-1) ... + z

(0, 1) tells us that the constant term z = 1.

because x = 0 eliminates all other terms. and as the sum is 1, that means z = 1.

for the other pairs I strongly suspect

(-1, 3) : 2×(-1)² + 1 = 2×1 + 1 = 3

(-2, 9) : 2×(-2)² + 1 = 2×4 + 1 = 9

so, the fitting equation is

y = 2x² + 1

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A college sends a survey to members of the class of 2012. Of the 1254 people who graduated that year, 672 are women, of whom 124
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Answer:

a) P(F) = \frac{672}{1254}=\frac{112}{209}=0.536

b) P(M) = \frac{582}{1254}= \frac{97}{209}=0.464

c) P(A') = 1-P(A) = 1- \frac{124}{672}= \frac{137}{168}=0.815

Step-by-step explanation:

For this case we have a total of 1254 people. 672 are women and 582 are female.

We know that 124 women wnat on to graduate school.

And 198 male want on to graduate school

We can define the following events:

F = The alumnus selected is female

M= The alumnus selected is male

A= Female and attend graduate school

And we can find the probabilities required using the empirical definition of probability like this:

Part a

P(F) = \frac{672}{1254}=\frac{112}{209}=0.536

Part b

P(M) = \frac{582}{1254}= \frac{97}{209}=0.464

Part c

For this case we find the probability for the event A: The student selected is female and did attend graduate school

P(A) =\frac{124}{672}=\frac{31}{168}=0.185

And using the complement rule we find P(A') representing the probability that the female selected did not attend graduate school like this:

P(A') = 1-P(A) = 1- \frac{124}{672}= \frac{137}{168}=0.815

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Alborosie

Answer:

0.105

Step-by-step explanation:

0.25/100 x 42 = 0.105

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