1*1+9∗0.001
Hope this helps
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
72.17 m to the nearest hundredth.
Step-by-step explanation:
It is sin not cos.
We use the Sine Rule to do this
a / sin A = b / sin C = c / sin C.
Here we have:
100 / sin 49 = x / sin 33
x = 100 * sin 33 / sin 49
= 72.17 m.
<em>V</em>≈301.59
I think this is the answer.
Hope this helps!
