Question

Solve for x in the following inequality: 3(-2x - 4) > 18

Answer 1

Answer:

$\boxed {\boxed {\sf x< -5}}$

Step-by-step explanation:

We are asked to solve the following inequality for x.

$3(-2x-4) > 18$

Solve for x by isolating it and performing the inverse operations.

3 is being multiplied by (-2x-4). The inverse operation of multiplication is division. Divide both sides of the inequality by 3.

$\frac {3(-2x-4)}{3} > \frac{18}{3}$

$(-2x-4) > \frac{18}{3}$

$-2x-4 > 6$

4 is being subtracted from -2x. The inverse operation of subtraction is addition. Add 4 to both sides of the inequality.

$-2x-4+4 > 6+4$

$-2x > 10$

x is being multiplied by -2. The inverse operation of multiplication is division. Divide both sides by -2.

$\frac {-2x}{-2} > \frac {10}{-2}$

$x> \frac {10}{-2}$

Since we divided by a negative number, the inequality sign must be flipped.

$x< \frac{10}{-2}$

$x < -5$

Answer 2

Answer:

x < -5

Step-by-step explanation:

3 ( -2x - 4 ) > 18

→ Expand the brackets

-6x - 12 > 18

→ Add 12 to both sides

-6x > 30

→ Divide both sides by -6

x < -5