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dexar [7]
2 years ago
9

Solve for x in the following inequality: 3(-2x - 4) > 18

Mathematics
2 answers:
grigory [225]2 years ago
7 0

Answer:

\boxed {\boxed {\sf x< -5}}

Step-by-step explanation:

We are asked to solve the following inequality for x.

3(-2x-4) > 18

Solve for x by isolating it and performing the inverse operations.

3 is being multiplied by (-2x-4). The inverse operation of multiplication is division. Divide both sides of the inequality by 3.

\frac {3(-2x-4)}{3} > \frac{18}{3}

(-2x-4) > \frac{18}{3}

-2x-4 > 6

4 is being subtracted from -2x. The inverse operation of subtraction is addition. Add 4 to both sides of the inequality.

-2x-4+4 > 6+4 \\

-2x > 10

x is being multiplied by -2. The inverse operation of multiplication is division. Divide both sides by -2.

\frac {-2x}{-2} > \frac {10}{-2}

x> \frac {10}{-2}

Since we divided by a negative number, the inequality sign must be flipped.

x< \frac{10}{-2}

x < -5

Schach [20]2 years ago
3 0

Answer:

x < -5

Step-by-step explanation:

3 ( -2x - 4 ) > 18

→ Expand the brackets

-6x - 12 > 18

→ Add 12 to both sides

-6x > 30

→ Divide both sides by -6

x < -5

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Compare the process of solving |x – 1| + 1 &lt; 15 to that of solving |x – 1| + 1 &gt; 15. Check all of the following you includ
zepelin [54]

The required Comparison of the inequalities are

  • The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.

The range of values encompassing the region's junction is (-13, 15).

  • If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.

<h3>What is inequality?</h3>

When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.

We take into account the various variables of the inequality

|x – 1| + 1 > 15

Therefore

|-x-1|+1-1<15-1

|-x-1|-1 <14

13<x<15

The required region lies between the inequality -13 <x< 15.

Simplify the inequality Ix-11+1 > 15 we get,

|x-1|+1 > 15

|x+1| +1-1 >15-1

|x-1| > 14

x> 15  

x<-13

  • If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
  • If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.

Read more about inequalities

brainly.com/question/20383699

#SPJ1

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2 years ago
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