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3 years ago

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What about this one a tennis ball has a radius of 1.25 inches. The outside of a tennis ball is covered with felt. How many squar

e inches of felt, to the nearest square inch, does it take to cover a tennis ball?

2 answers:

inessss [21]3 years ago

3 0

The surface area of a sphere is given by the formula
.. A = 4π*r^2
.. A = 4π*(1.25 in)^2 ≈ 20 in^2

Maslowich3 years ago

3 0

It takes approximately 20 square inches of felt to cover a tennis ball.

Explanation

A tennis ball is in shape of a Sphere. As the outside of the ball is covered with felt, so we need to find the surface area of the ball.

Formula for surface area of sphere: $A= 4\pi r^2$

where, $r$ is the radius of the sphere.

Here the radius is given as 1.25 inch, so $r=1.25$

Thus,

$A= 4\pi (1.25)^2\\ \\ A= 4(3.14)(1.5625)\\ \\ A= 19.625\\ \\ A= 20 (Approximately)$

So, it takes approximately 20 square inches of felt to cover a tennis ball.

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Shtirlitz [24]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

$\qquad \sf \dashrightarrow \:c = \pi d$

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

$\qquad \sf \dashrightarrow \:c = 2\pi r$

Now, let's move on to questions ~

<h3>First </h3>

$\qquad \sf \dashrightarrow \:3.14 \times 5.9$

$\qquad \sf \dashrightarrow \: \approx18.53 \: ft$

<h3 />

・．━━━━━━━†━━━━━━━━━．・

<h3>Second</h3><h3 /><h3 /><h3 /><h3> $\qquad \sf \dashrightarrow \:3.14 \times 3.2$ </h3>

$\qquad \sf \dashrightarrow \: \approx10.048 \: ft$

・．━━━━━━━†━━━━━━━━━．・

<h3>Third</h3>

$\qquad \sf \dashrightarrow \:3.14 \times 6.1$

$\qquad \sf \dashrightarrow \: \approx19.15 \: ft$

・．━━━━━━━†━━━━━━━━━．・

<h3>Fourth</h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 3.7$

$\qquad \sf \dashrightarrow \: \approx2×11.62 \: m$

$\qquad \sf \dashrightarrow \: \approx23.24 \: m$

・．━━━━━━━†━━━━━━━━━．・

<h3>Fifth </h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 6.2$

$\qquad \sf \dashrightarrow \: \approx2× 19.47 \: units$

$\qquad \sf \dashrightarrow \: \approx38.94 \: m$

・．━━━━━━━†━━━━━━━━━．・

<h3>Sixth</h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 5.1$

$\qquad \sf \dashrightarrow \: \approx2×16.01 \: ft$

$\qquad \sf \dashrightarrow \: \approx \: 32.02m$

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