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diamong [38]
3 years ago
5

What about this one a tennis ball has a radius of 1.25 inches. The outside of a tennis ball is covered with felt. How many squar

e inches of felt, to the nearest square inch, does it take to cover a tennis ball?
Mathematics
2 answers:
inessss [21]3 years ago
3 0
The surface area of a sphere is given by the formula
.. A = 4π*r^2
.. A = 4π*(1.25 in)^2 ≈ 20 in^2
Maslowich3 years ago
3 0

It takes approximately 20 square inches of felt to cover a tennis ball.

Explanation

A tennis ball is in shape of a Sphere. As the outside of the ball is covered with felt, so we need to find the surface area of the ball.

Formula for surface area of sphere: A= 4\pi r^2

where, r is the radius of the sphere.

Here the radius is given as 1.25 inch, so r=1.25

Thus,

A= 4\pi (1.25)^2\\ \\ A= 4(3.14)(1.5625)\\ \\ A= 19.625\\ \\ A= 20 (Approximately)

So, it takes approximately 20 square inches of felt to cover a tennis ball.

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What’s distributive property to express 36+16
Gennadij [26K]

Factors of 36 are 18,12,9,6,4,3,2,1

The common factor of 16 and 36 are 4,2,1

5 0
3 years ago
A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. How much water must be added to accompli
Verizon [17]

Answer:

The amount of water must be added to this task = 60 cm^{3}

Step-by-step explanation:

Let amount of water added = x cm^{3}

Then from the given conditions

A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. So

90 (0.05) = 0.03 ( 90 + x )

4.5 = 2.7 + 0.03 x

0.03 x = 1.8

x = 60 cm^{3}

Therefore the amount of water must be added to this task = 60 cm^{3}

8 0
3 years ago
Convert. If necessary, round to the nearest tenth. (Recall: 1.06 qt. ≈ 1 L) 15 L qt. a. 15.9 c. 13.4 b. 159 d. 134
Makovka662 [10]
The answer is a. 15 L x 1.06= 15.9
4 0
3 years ago
!!!!!! URGENT PLS HELP ME ANSWER !!!!
laila [671]

Answer:

1) A = 547.1136, C = 82.896

2) A = 678.5226, C = 92.316

3) A = 844.5344, C = 102.992

4) A = 1554.49625, C = 139.73

5) A = 1561.4906, C = 140.044

6) A = 994.8776, C = 111.784

Step-by-step explanation:

1)

A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{26.4}{2})^2 = 3.14 * 13.2^2 = 547.1136

C = \Pi D = 3.14 * 26.4 = 82.896

2)

A = \Pi r^2 = 3.14*(14.7)^2 = 678.5226

C = 2\Pi r = 14.7*2 * 3.14 = 92.316

3)

A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{32.8}{2})^2 = 3.14 * 16.4^2 = 844.5344

C = \Pi D = 3.14 * 32.8 = 102.992

4)

A = \Pi (\frac{D}{2})^2 =  3.14 * (\frac{44.5}{2})^2 = 3.14 * 22.25^2 = 1554.49625

C = \Pi D = 44.5*3.14 = 139.73

5)

A = \Pi r^2 = 3.14*22.3^2 = 1561.4906

C = 2\Pi r = 2 * 3.14 * 22.3 = 140.044

6)

A = \Pi r^2 = 3.14 * 17.8^2 = 994.8776

C = 2\Pi r = 2 * 3.14 * 17.8 = 111.784

8 0
2 years ago
An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 4385 feet and Plane B is at an altitude
Fantom [35]

Answer:

60 seconds, 7715 feet

Step-by-step explanation:

Plane A and B start out 615 feet apart, and we find this by subtracting the height of plane A from plane B, getting 5000-4385=615. Now we have to find how many more feet of altitude plane A is gaining per second over plane B.

To find this we subtract 45.25 from 55.5 and get 10.25 feet per second. Now to find out how many seconds until they'll be at the same altitude we simply divide 615 by 10.25, getting 60 seconds.

For the second part, to find the altitude at this point, we simply multiply the altitude gain of one of the planes per second by the time of 60 seconds to get how much altitude they gained over that time, and add it to the starting altitude. Doing this with plane B we get 45.25*60=2715, and we add that to 5000 to get the final answer of 7715.

4 0
3 years ago
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