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nikdorinn [45]
2 years ago
12

Help plz:

Mathematics
1 answer:
Mice21 [21]2 years ago
6 0

Step-by-step explanation:

you will see, this is totally easy. so, once you understand that principle, I am sure you will agree with me that this costs more time putting it in here than just doing it yourself in the future.

you need to consider for addition and subtraction every variable combined with an exponent a different thing, a fruit for example.

you know exactly what to do, when you are being asked to add 3 apples to 2 apples, right ?

or, when are are asked to add 4 apples and 2 pears to 3 apples and 2 pears.

in the first case we simply get 5 (2+3) apples.

in the second case we get 7 (3+4) apples and 4 (2+2) pears.

and nothing else happens here.

we could call x² apples, y² pears, y³ plums, x kiwis, t strawberries, t² raspberries. and the constants could be another fruit or grams of sugar.

now, we simply combine the "fruits" that belong together. there is nothing more to this.

5x² + 3y³ - 4x² = x² - 3y³ (because 5-4 for x²)

y³ + 2y³ - 8 + 2 = 3y³ - 6 (1+2 for y³ and -8+2 constant)

9 - 3x - 4x + 2x - 12 = -5x - 3

-6t + 4t² - 6 + 7t - 4t² = t - 6 (4-4 for t², -6+7 for t)

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Answer:

f(x) = 26500 * (0.925)^x

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Step-by-step explanation:

A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.

To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.

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