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AfilCa [17]
4 years ago
13

Liam says that the graph of the function between x=1 and x=3 is non linear and increasing . What error could he have made in ana

lyzing the graph ?
A) he did not make an error

B) he mistakenly identified this interval as increasing

C) he was looking at the interval between between x= 3 and x=4

D) he was looking at the interval between x= 4 and x= 6

Mathematics
1 answer:
____ [38]4 years ago
7 0
I would say that (d) is the correct answer because the section between x=4 and x=6 is not linear but exponential but it is still increasing. The section between x=1 and x=3 however is linear and therefore his answer is incorrect. 
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THERE ARE 52 WEEKS IN A YEAR.
40 (hours) x 52 (weeks) = 2080
29460 / 2080 = 14.25

He made a. $14.25 per hour.
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Which of the following polynomials is in standard form?
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D. f(x)= x*-9x^o+2x^2-4x+10
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I'LL GIVE YOU 5 STARES HELP. Find the area of the figures shown below and drop the correct result Into the appropriate blank. DR
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I saw its strength
It pushed and shoved
Moving spring into the past I felt its determination.
It talked with conviction,
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It permeated the air,
Providing support and desire. I heard its voice.
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It sheltered my fears,
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Summer spoke to me.

How does the first–person perspective in the poem reinforce the idea that summer is an actual being?

a
It is omniscient, which means that it knows everything, so summer must be an actual being.
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3 years ago
Why will the ratio of the volume of the two cubes with side lengths in the ratio of 1:2 be 1:8
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Answer: 1³ = 1

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1:8

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So the cubic ratio of 1:2 is 1:8

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3 years ago
Suppose that we are testing H0 : 0 versus H1 : 0 with a sample size of n 10. Calculate bounds on the P-value for the following o
stepan [7]

Answer:

a) p_V = 2*P(t_{9} >|2.48|) =0.0349

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"

0.03 < p_v

b) p_V = 2*P(t_{9} >|-3.95|)=0.003355

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"

p_v

c) p_V = 2*P(t_{9} >|2.69|) =0.02480

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"

0.01 < p_v

d) p_V = 2*P(t_{9} >|1.88|) =0.09281

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"

0.05 < p_v

Step-by-step explanation:

For this case we are testing the following system of hypothesis:

Null hypothesis: \mu =0

Alternative hypothesis: \mu \neq 0

The sample size is n=10, so then the degrees of freedom are given by:

df=n-1= 10-1=9

In order to calculate the p value we can use the fact that we are conducting a bilateral test so then the p value is given by:

p_V = 2*P(t_{9} >|t_0|)

Where t_0 represent the calculated or observed statistic.

a) t0= 2.48

p_V = 2*P(t_{9} >|2.48|) =0.0349

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"

0.03 < p_v

b) t0= -3.95

p_V = 2*P(t_{9} >|-3.95|)=0.003355

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"

p_v

c) t0=2.69

p_V = 2*P(t_{9} >|2.69|) =0.02480

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"

0.01 < p_v

d) t0=1.88

p_V = 2*P(t_{9} >|1.88|) =0.09281

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"

0.05 < p_v

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