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makkiz [27]
3 years ago
12

Quadratic Functions Put the equationy = x^2 + 14a + 40 into the form y = (x - h )^2 + k: Answer: y Preview Get help: Video Poins

Mathematics
1 answer:
Setler [38]3 years ago
7 0

Answer:  y=(x+7)^2-9 where h=-7 and k=-9

Step-by-step explanation:

We need to "complete the square",

A perfect square trinomial formule is:

(a+b)^{2}=a+2ab+b^{2}

in this case, a is x and to find -h we know that 14x is 2*x*(-h) so:

14x=2*x*(-h)

14x/2x=-h (x is simplified)

7=-h => h=-7

we add +7^2 and -7^2, to the first equation:  

y= <u>x^2 + 14x + 7^2</u> -7^2 + 40 (the underlined section is a perfect square trinomial already)

y=(x+7)^2 <u>-49 +40</u> (addition)

y= (x+7)^2 - 9

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A tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. If the tottoise walks the first part and
Ugo [173]

Answer:

120

240

Step-by-step explanation:

We call the length of first part x

Length of second part = y

In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.

So,

We have this equation,

x/4 + y/3 = 110

We take the LCM

(3x + 4y)/12 = 110

When we cross multiply

3x + 4y = 110x12

3x + 4y = 1320 ----- equation 1

For scenario 2

x/3 + y/4 = 100

When we take the LCM

(4x + 3y)/12 = 100

We cross multiply

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4x + 3y = 1200 ------ equation 2

We now have two equations and we will solve for x and y using simultaneous linear equation.

3x + 4y = 1320 ----- 1

4x + 3y = 1200 ----- 2

We subtract equation 2 from 1 to get

- x + y = 120

We make y subject

y = x + 120 ----- 3

We put the value of y in equation 3 into equation 1

3x + 4(x + 120) = 1320

3x + 4x + 480 = 1320

7x + 480 = 1320

7x = 1320-480

7x = 840

We divide through by 7

x = 840/7

x = 120

We put value of x in equation 3

y = x + 120

y = 120 + 120

y = 240

120 and 240 are the lengths of the 2 parts of the journey.

Thanks

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3 years ago
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Answer:

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Step-by-step explanation:

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icang [17]

Answer:

\huge\boxed{14\ \text{and}\ 7}

Step-by-step explanation:

n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right

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Answer:

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Step-by-step explanation:

Add all of them then divide.

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