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makkiz [27]
3 years ago
12

Quadratic Functions Put the equationy = x^2 + 14a + 40 into the form y = (x - h )^2 + k: Answer: y Preview Get help: Video Poins

Mathematics
1 answer:
Setler [38]3 years ago
7 0

Answer:  y=(x+7)^2-9 where h=-7 and k=-9

Step-by-step explanation:

We need to "complete the square",

A perfect square trinomial formule is:

(a+b)^{2}=a+2ab+b^{2}

in this case, a is x and to find -h we know that 14x is 2*x*(-h) so:

14x=2*x*(-h)

14x/2x=-h (x is simplified)

7=-h => h=-7

we add +7^2 and -7^2, to the first equation:  

y= <u>x^2 + 14x + 7^2</u> -7^2 + 40 (the underlined section is a perfect square trinomial already)

y=(x+7)^2 <u>-49 +40</u> (addition)

y= (x+7)^2 - 9

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gtnhenbr [62]
19.
Option (B) is the correct one.

Explanation:

The equation of line be is ,
y = 2x-4,

we have general equation give by,
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wherr m is the slope of the line and x and y are the coordinates changing,

Comparing these two we get the slop of line B as 2.

A thing you need to know here that product of slopes of a line perpendicular to another is -1.
Using this relation,

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Let A pass through a coordinate (x,y).

Now,

Slope will be give by,
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20.
Option (A) is the correct one.

How?:

Equation of line B is y = 3x-1.

Once again using the general equation for a line,
y =mx+c
Slope of B will be 3.

Now for a pair of parallel lines their slopes are equal.

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Slope of A must also be 3.

Applying the generation equation for a line on A gives,

y = 3x+c

Since A is passing though coordinates (2,4) the values must satisfy this equation,

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4 = 2(3) + c \\ c = 4 - 6 = - 2
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5 0
4 years ago
Someone help a friend out please on algebra?
IgorC [24]

Answer:

b. second answer.

Step-by-step explanation:

I think b.

I replaced the x in x-2 with 2, and the x in x+3 with -3, and got zero on both. 0x0=0

2/0=undefined

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<h2>1</h2>

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35/35 = 1 (certain)

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I'm always happy to help :)

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