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Komok [63]
3 years ago
5

How can i know the valence electron for the big elements

Chemistry
2 answers:
Masja [62]3 years ago
6 0
Use the group numbers to determine the number of valence electrons. The Group number of a non-transition metal can be used to find the number of valence electrons in an atom of that element. The ones place of the group number is the number of valence electrons in an atom of these elements.
pantera1 [17]3 years ago
4 0

Answer:

the group number of the element shows the number of valence electrons. for example, if you want to find the valence electron of oxygen, you see that it is in group 16 on the periodic table, so you look at the last number which is 6, meaning oxygen has 6 valence electrons.

Explanation:

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By which mechanism would a steroid molecule diffuse into the cell?
LUCKY_DIMON [66]

Answer: Directly through the phospholipid membrane

Explanation:

The cell membrane consist of a phospholipid bilayers structure. In the interior of the membrane, the phospholipid tail are hydrophobic, which makes the cell membrane to be selectively permeable, it is permeable to non polar molecules and impermeable to polar molecules.

Because Steroids are fat soluble, non polar compounds, they can diffuse directly through the hydrophobic, non polar core of the phospholipid bilayer without the use of carrier proteins.

5 0
3 years ago
You find a clean 100-ml beaker, label it "#1", and place it on a tared electronic balance. You add small amount of unknown solid
Ilia_Sergeevich [38]

Answer:

the mas is .291 g

Explanation:

the mass of a object does not change. so when added the substance the beaker. you had the mass of both objects together. you know the mass of the beaker and you know the mass of both. since mass does not change. the beakers mass is still 74.605g. the mass of both objects is 74.896. all you have to do is subtract the mass of the beaker from the total mass. 74.896 - 74.605 equals .291g. so the mass of the unknown substance Is .291g

7 0
3 years ago
PLEASE HELP ASAP!
Airida [17]

Answer:

Direct relationship

Explanation:

I took the test. Good luck!

7 0
3 years ago
Read 2 more answers
List all possible oxidation numbers for the elements. 21. Al
Alex73 [517]

Answer:

21. Al (Aluminium)

+3 (most common), -1, -2, +1, +2

22. Bi (Bismuth)

+3 (most common), -3, -2, -1, +1, +2, +4, +5

23. Ni (Nickel)

+2 (most common), -2, -1, 0,+1, +3, +4

24. Xe (Xenon)

0 (most common), +1, +2, +4, +6, +8

25. Pb (Lead)

+2 (most common), +4 (most common), -4, -2, -1, +1, +3

Explanation:

Now we proceed to present the answers for each element:

21. Al (Aluminium)

+3 (most common), -1, -2, +1, +2

22. Bi (Bismuth)

+3 (most common), -3, -2, -1, +1, +2, +4, +5

23. Ni (Nickel)

+2 (most common), -2, -1, 0,+1, +3, +4

24. Xe (Xenon)

0 (most common), +1, +2, +4, +6, +8

25. Pb (Lead)

+2 (most common), +4 (most common), -4, -2, -1, +1, +3

7 0
3 years ago
How is a heterogeneous mixture different from a homogeneous mixture?
MArishka [77]
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6 0
4 years ago
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