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Citrus2011 [14]
3 years ago
14

The value of the Solubility Product Constant for lead phosphate is ____________

Chemistry
1 answer:
emmasim [6.3K]3 years ago
4 0

<u>Answer:</u> The reaction for the K_{sp} value of lead phosphate is given below and the value of solubility product for the same is 3.0\rightarrow 10^{-44}

<u>Explanation:</u>

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is expressed as K_{sp}

The chemical formula of lead phosphate is Pb_3(PO_4)_2

The equation for the hydration of the lead phosphate is given as:

Pb_3(PO_4)_2(s)+H_2O(l)\rightarrow 3Pb^{2+}(aq.)+2PO_4^{3-}(aq.)

The solubility product of lead phosphate is 3.0\rightarrow 10^{-44}. This means that it is highly insoluble in water as the solubility product is very very low.

Hence, the reaction for the K_{sp} value of lead phosphate is given above and the value of solubility product for the same is 3.0\rightarrow 10^{-44}

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Explain what happens to the heat that is being added to a substance when the substance is changing phase.
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3 years ago
What volume of a 0.550 M solution of potassium hydroxide (KOH) can be made with 19.9 g of potassium hydroxide?
Natalija [7]

Answer:

0.645 L

Explanation:

To find the volume, you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio). The final answer should have 3 sig figs to match the sig figs of the given values.

(Step 1)

Molar Mass (KOH): 39.098 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (KOH): 56.104 g/mol

19.9 grams KOH              1 mole
--------------------------  x  -----------------------  =  0.355 moles KOH
                                     56.014 grams

(Step 2)

Molarity = moles / volume                            <----- Molarity ratio

0.550 M = 0.355 moles / volume                 <----- Insert values

(0.550 M) x volume = 0.355 moles              <----- Multiply both sides by volume

volume = 0.645 L                                          <----- Divide both sides by 0.550

6 0
1 year ago
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