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algol [13]
2 years ago
11

1/2(10p-7q) if p=9 and q=2

Mathematics
1 answer:
Gala2k [10]2 years ago
3 0

Answer:

38

Step-by-step explanation:

1/2(10p-7q)

1/2(10(9)-7(2))

1/2(90-14)

1/2(76)

76/2

38

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Nancy hears a report that the
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The difference in the averages depends on the range between the gas prices and how often they appear in the given set of data.
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3 years ago
One customer purchases 8 bags of cat food and 2 bags of dog food. The total weight of the purchase is 44 pounds. Another custome
Umnica [9.8K]

Answer:

answer is x=3 and y=10

Step-by-step explanation:

Forgot to isolate y and x and simplify

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3 years ago
A store brought 9 cases of light bulbs in May and 8 cases in June. There are 48 light bulbs in a case. How many light bulbs did
UkoKoshka [18]
So the store bought 9 cases of lightbulbs and in a case, there are 48.
9 * 48 = the number of lightbulbs in the nine cases. 432 is the number of light bulbs in the 9 cases they bought in May. So then let's move on to the cases they bought in June. Do the same thing 8 * 48 is 384. So then add the two amounts together and then you will get 816 which will be your answer. I hope this helps!
5 0
3 years ago
Read 2 more answers
This one tooooo and the whole thing
cluponka [151]

Answer:

4 5/8 the answer you have is correct :)

Step-by-step explanation:

First, you want to make the mixed fraction into an improper fraction.

 7 x 4 + 3 = 31 (31/4)

3 x 8 + 1 = 25 (25/8)

Now you want them both to have a common denominator.

31/4 x 2/2 = 62/8

Now you are ready to subtract!

62/8 - 25/8 = 37/8

Finally, convert 37/8 to a proper fraction.

37/8 = 4 5/8

8 0
3 years ago
In 1912, the RMS Titanic, a British passenger ship, sank in the North Atlantic Ocean after colliding with an iceberg. Historians
denpristay [2]

Answer:

The probability that a surviving passenger belongs to second-class cabin passengers is \frac{118}{285} = 0.414

Step-by-step explanation:

Let's define the events:

S: The passenger survived.

NS: The passenger did NOT survive.

C2: The passenger belonged to a second class cabin.

NC2: The passenger did not belong to a second class cabin.

With these events and the information provided the probability are:

P (S) = 711/2201

P(NS) = 1490/2201

P(C2) = 285/2201

P (NC2) = 1495/2201

The probability that a surviving passenger belongs to second-class cabin passengers is:

P (S | C2) = \frac{P(S\bigcapC2)}{P(C2)} = \frac{\frac{118}{2201}}{\frac{285}{2201}} = \frac{118}{285} = 0.414

7 0
4 years ago
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