Answer:
Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.
Answer:
3/-4
Step by step explanation:
Answer:
Area- 910
Perimeter- 152
Answer:
84
I think so
Step-by-step explanation:
i dont know
PEMDAS (right to left) (Parentheses, exponents, Multiplication/Division, Addition/Subtraction) or Please Excuse My Dear Aunt Sally is what I was taught to use.
1.[(-4)+{-2}]*(-5)^2-9; divide 8 by -4 (it is the innermost parentheses problem)
2. [(-6)]*-5^2-9; next innermost parentheses problem
3. [(-6)]*25-9; exponents
4. -150-9; multiplication
5. -159; subtraction/addition depending on how you want to look at it