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Tamiku [17]
3 years ago
13

A circle has a diameter of 28 ft. What is the circumference?

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0
<span>circumference of a circle   = TT x d                 where TT= 3.14 

c= 3.14 x 28 = 87.92 ft</span>
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A ___ is an exponential expression with 10 as the base.
bagirrra123 [75]

Answer:

power of ten

Step-by-step explanation:

A power of ten is an exponential expression with 10 as the base. The first few power of tens (nonnegative) are 1, 10, 100, 1,000, and so on.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

4 0
2 years ago
People travel by bus or by train from hiraddug station on tuesday 420 people travelled by bus from the station the ratio of the
goldenfox [79]

The number of people travelled by train from the station on tuesday is 357.

Let us assume the number of people who travelled by train from the station on tuesday be x. Using the concept of ratio and proportion to solve and calculate x.

Forming the ratio-

20 : 17 = 420 : x

Solving the ratio and proportion for the value of x

x = (420 × 17) ÷ 20

Performing multiplication in numerator

x = 7140 ÷ 20

Performing division on Right Hand Side of the equation

x = 357

Therefore, based on the information, 357 people used to travel.

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3 0
10 months ago
To finance a bridge costing $94,500, the state contributed twice as much as the county and the county contributed twice as much
bearhunter [10]
The city contributed $13,500; the county contributed $27,000; and the state contributed $54,000.

Let x be the amount the city contributes.  Since the county contributes twice as much as the city, the county's amount is 2x.  Since the state contributes twice as much as the county, the state's amount is 2(2x) = 4x.

They total 94,500:
x+2x+4x = 94500
7x = 94500

Divide both sides by 7:
x = 13500
2x = 27000
4x = 54000
5 0
3 years ago
Which of the following is the missing reason? Statements Reasons two thirds times x plus 7 equals negative 5 Given 2x 21 = â’15
pentagon [3]

The correct option is B. Distributive property

Given,

\frac{2}{3} x+7=-5\\

On solving the above equation,

multiplying both sides by 3 we, get

2x+21=-15

now subtracting 21 from both the sides,

2x=-36\\

dividing both the sides by 2 we get,

x=-18

Since in the above steps we follow all the giving property except the distributive property.

Hence the correct option is B. Distributive property.

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brainly.com/question/13130806

6 0
2 years ago
Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
2 years ago
Read 2 more answers
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