we have that
−4+8−16+32−.....
a1=-2*(-2)-----> -4
a2=-4*(-2)-----> +8
a3=+8*(-2)-----> -16
a4=-16*(-2)----> +32
a5=+32*(-2)----> -64
a6=-64*(-2)-----> +128
a7=+128*(-2)-----> -256
The sum of the first 7 terms of the series is
<span>[a1+a2+a3+a4+a5+a6+a7]-----> [-4+8-16+32-64+128-256]------->
-172</span>
<span>
the answer is -172</span>
I believe the answer to be C. You would move the decimal place over 3 to the left. Leaving it to be .00818 or 0.00818
Answer: a = 10
Step-by-step explanation: 6a + 12 = 72
-12 -12
6a = 60
6a/6 = 60/6
a = 10
Answer:
10, 14
Step-by-step explanation:
A + B = 24, so A = 24 - B
5.8A + 7.4B = 161.6
Substitute the first equation into the second
5.8(24 - B) + 7.4B = 161.6
139.2 - 5.8B + 7.4B = 161.6
139.2 + 1.6B = 161.6
1.6B = 22.4
B = 14, So he works 14 hours at job B.
Together they make 24, so he works 10 hours at job A.
Answer:
The probability that a randomly selected customer orders a pizza or a salad is 80%
Step-by-step explanation:
Let's call
= the proability of someone asking for a pizza
= the probability that a customer orders a salad
Pp∩s = the probability that a customer orders a pizza and a salad.
We know from the statement of the problem that:
= 70% = 0.7
= 25% = 0.25
Pp∩s = 15% = 0.15
We want to know the probability that a randomly selected customer will order a pizza or a salad. Then, by set theory, that probability is calculated as:
Pp∪s = ∪ - Pp∩s
So:
Pp∪s = Pp + Ps - Pp∩s
Where Pp∪e is the probability that the customer orders a pizza or a salad, but not both at the same time.
Pp∪e = 0.7 + 0.25 -0.15
Pp∪e = 0.8
Finally, the probability that a randomly selected customer orders a pizza or a salad is 80%
