We shall use the formula for distance traveled:
s = ut + (1/2)at^2
where
u = initial velocity
t = time
a = acceleration.
Because
u = 0 (car starts from rest),
t = 10 s (travel tme),
a = 2 m/s^2 (acceleration), m
the di mstance traveled is
s = (1/2)*(2 m/s^2)*(10 s)^2 = (1/2)*2*100 = 100
Answer: 100 m
Is there a question here? I can't see it!
