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3 years ago

For a Cylinder: radius = 6mm Vertical eight = 9 mm, find Total surface area

Mathematics

2 answers:

lozanna [386]3 years ago

7 0

Surface area is 2pi r h +. 2pi r squared
2 pi 6 9 + 2 pi 6^2
= 108 pi + 72 pi
= 180 pi

Whitepunk [10]3 years ago

3 0

Answer:

Total surface area is 565.5 mm²

Step-by-step explanation:

${ \rm{total \: s.a = 2\pi rh + 2\pi {r}^{2} }} \\ \\ { \rm{total \: s.a = 2\pi r(h + r)}}$

h is height
r is radius

${ \rm{total \: s.a = (2 \times 3.14 \times 6)(9 + 6)}} \\ \\ { \rm{total \: s.a = 565.5 \: {mm}^{2} }}$

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3 years ago

Evaluate (-28) + 38 + (-12). EXPLAIN YOUR ANSWER, I KNOW IT’S -2, BUT WHY? How do I get -2? I am asking you to explain how you s

kipiarov [429]

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If the sign before the no. is same then they will get added and the resultant will have the same sign too.

Since before 28 and 12 , both of them have the negative sign , they will get added and the sign of their resultant will be negative too.

So , -28-12 = -40

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3 years ago

Given GHI G (4,-3), H (-4,2), and I (2,4), find the perpendicular bisector of HI in standard form.

Olin [163]

Answer:

$3x+y=0$

Step-by-step explanation:

step 1

Find the slope of segment HI

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

H (-4,2), and I (2,4)

substitute the given points

$m=\frac{4-2}{2+4}$

$m=\frac{2}{6}$

simplify

$m=\frac{1}{3}$

step 2

Find the slope of the perpendicular line to segment HI

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=\frac{1}{3}$

$m_2=-3$

step 3

Find the midpoint segment HI

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

H (-4,2), and I (2,4)

substitute

$M(\frac{-4+2}{2},\frac{2+4}{2})$

$M(-1,3)$

step 4

we know that

The perpendicular bisector of HI is a line perpendicular to HI that passes though the midpoint of HI

Find the equation of the perpendicular bisector of HI in point slope form

$y-y1=m(x-x1)$

we have

$m=-3$

$M(-1,3)$

substitute

$y-3=-3(x+1)$

step 5

Convert to slope intercept form

$y=mx+b$

Isolate the variable y

$y-3=-3x-3$

$y=-3x-3+3$

$y=-3x$

step 6

Convert to standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

$y=-3x$

Adds 3x both sides

$3x+y=0$

see the attached figure to better understand the problem

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