All categories

4 years ago

A student bought 84 pencils. If he sharpened 35 pencils, what is the ratio of the unsharpened pencils to the sharpened pencils?

1 answer:

6 0

Number of pencils bough by the student = 84
Number of pencils sharpened by the student = 35
Then
The number of pencils that was not sharpened = (84 - 35)
= 49
So 35 pencils have been sharpened and 49 pencils have not been sharpened.
Then Number of pencils unsharpened:Number of pencils sharpened = 49:35
= 7:5
So the ratio of the number of unsharpened pencil to the number of sharpened pencil is 7:5

You might be interested in

What are the 2 values that fill in both lines?

hjlf

(assuming if the a is positive)
If b is greater than 1 the function is increasing

if b is between 0 and 1, the function is decreasing

5 0

3 years ago

Jon is decorating a panner for a parade. Jon uses a piece of red ribbon witch is 3 4ths yard long. Jon also needs blue ribbon th

SVEN [57.7K]

Answer:

John needs $3\frac{3}{4}$ yards of blue ribbon.

Step-by-step explanation:

We have been given that Jon uses a piece of red ribbon witch is 3/4th yard long. Jon also needs blue ribbon that is 5 times as long as the ribbon. We are asked to find the amount of blue ribbon that John needs.

To find the amount of blue ribbon that John needs, we will multiply amount of red ribbon by 5 as shown below:

$\text{Amount of blue ribbon}=5\times \frac{3}{4}$

$\text{Amount of blue ribbon}=\frac{5\times 3}{4}$

$\text{Amount of blue ribbon}=\frac{15}{4}$

$\text{Amount of blue ribbon}=3\frac{3}{4}$

Therefore, John needs $3\frac{3}{4}$ yards of blue ribbon.

8 0

3 years ago

A heavy rope, 30 ft long, weighs 0.4 lb/ft and hangs over the edge of a building 80 ft high. Approximate the required work by a

gizmo_the_mogwai [7]

Answer:

180 fb*lb

45 ft*lb

Step-by-step explanation:

We have that the work is equal to:

W = F * d

but when the force is constant and in this case, it is changing.

therefore it would be:

$W = \int\limits^b_ a {F(x)} \, dx$

Where a = 0 and b = 30.

F (x) = 0.4 * x

Therefore, we replace and we would be left with:

$W = \int\limits^b_a {0.4*x} \, dx$

We integrate and we have:

W = 0.4 / 2 * x ^ 2

W = 0.2 * (x ^ 2) from 0 to 30, we replace:

W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)

W = 180 ft * lb

Now in the second part it is the same, but the integral would be from 0 to 15.

we replace:

W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)

W = 45 ft * lb

6 0

3 years ago

A force of $20$ newtons will stretch a spring $5$ centimeters. What is the total number of centimeters that a force of $60$ newt

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Hooke's Law applies here, which is a linear relationship. It would be easier to solve this using proportions with N of force on the top and the amount of stretch in cm on the bottom. Set up with our unknown, the number of cm:

$\frac{N}{cm}:\frac{20}{5}=\frac{60}{x}$ and cross multiply:

20x = 300 so

x = 15 cm

6 0

3 years ago

You earn $1,166 gross taxable income every week, and have claimed no exemptions. Assuming that you have no other sources of inco

VLD [36.1K]

Answer:

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers