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kaheart [24]
3 years ago
5

Help help help help help help me please

Mathematics
2 answers:
ira [324]3 years ago
6 0

Answer:

B

Step-by-step explanation:

trapecia [35]3 years ago
5 0

Answer:

Option B

Step-by-step explanation:

to find the answer, you're going to break the phrase into different parts

these parts would be "13 more than", and "the product of 4 and a number, n"

"13 more than" means that you are adding 13 to the pile, so algebraically, this would be written as "+13" or "13+"

"the product of 4 and a number, n" is one thing, but it can be broken down even further to "the product of" and "4 and a number, n"

"the product of" means a multiplication sign, I know this because the term for the answer of multiplying numbers is "product"

"4 and a number, n" means that it is one thing that includes 4 and <em>n </em>together, so this would create 4n

if you put this all together, you would get "4n + 13" or "13 + 4n", these are the same thing, just written in different orders

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Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.
Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: \mathbf{y=-2x+11}

Equation of the line that passes through the given point and is (b) perpendicular is: \mathbf{y=\frac{1}{2}x+1}

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have points (1,6) and (2,2)

Slope is:

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11

The equation of line will be:

y=mx+b\\y=-2x+11

Equation of the line that passes through the given point and is (a) parallel is: \mathbf{y=-2x+11}

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1

The equation of line will be:

y=mx+b\\y=\frac{1}{2}x+1

Equation of the line that passes through the given point and is (b) perpendicular is: \mathbf{y=\frac{1}{2}x+1}

6 0
3 years ago
A rectangle has a perimeter of 48cm. The length is twice the width. What is the area? (NEEDED ASAP)
Vanyuwa [196]

Answer:

128cm^2

Step-by-step explanation:

The length is 16 and the width is 8. 16*8=128.

4 0
3 years ago
How do you do _+-5=-13
GalinKa [24]
First make the dash an x. Then move over to the other side of the = so it looks like this:
-5=-13-x
You take -13 to the other side of the equal sign so it looks like this:
-5+13=-x
Then:
8=-x or x=-8
Hopefully that makes sense.
5 0
4 years ago
Read 2 more answers
Question 1 [5 points]
RideAnS [48]
If I’m not wrong, it should be 1000-5+9.10% and add it to the tune and divide with the 9.90% and -3 and then you can get your answer
6 0
3 years ago
A rock is thrown up from the ground at a velocity of 84 feet per second. The formula h = -16t2 + 84t gives the rock's height in
kenny6666 [7]

Answer:

h = 110.24 m

Step-by-step explanation:

It is given that,

A rock is thrown up from the ground at a velocity of 84 feet per second. The formula h = -16t^2 + 84t gives the rock's height in feet after t second.

We need to find the maximum height of the rock. For maximum height put \dfrac{dh}{dt}=0

So,

\dfrac{d( -16t^2 + 84t)}{dt}=0\\\\-32t+84=0\\\\t=\dfrac{84}{32}\\\\t=2.62\ s

Put t = 2.62 s in the equation of height. So,

h = -16(2.62)^2 + 84(2.62)\\\\h=110.24\ m

So, the maximum height of the rock is 110.24 m.

7 0
3 years ago
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