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bogdanovich [222]
2 years ago
11

Solve 3|x+2|<12. Graph the solutions on the number line.

Mathematics
1 answer:
VikaD [51]2 years ago
5 0

Answer:

-6<x<2

Step-by-step explanation:

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A jar contains n nickels and d dimes. There are 24 coins in the jar, and the total value of the coins is $1.90. How many nickels
oee [108]

Answer:14 dimes 10 nickels

Step-by-step explanation:

24 coins total

14 X.10 = 1.40

10 x .05 = .50

1.40 + .50 = 1.90

3 0
3 years ago
Five members of the computer club site to buy used computer dividing up the cost equally later three new members join a club of
BartSMP [9]

The computation shows that the price of the used computer is $75.

<h3>How to compute the price?</h3>

From the information given, it should be noted that there are 5 members before the new members joined and $15 was given to each member.

Therefore, the price of the used computer will be:

= $15 × 5

= $75

The price of the used computer is $75.

Learn more about computations on:

brainly.com/question/4658834

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7 0
1 year ago
!*I NEED HELP AND QUICK*!
rewona [7]
1)96/8=12
2)(95*6+5)/6 : (24+1)/3 = (95*6+5)/6 : 2*25/6 = 575/6 *6/50=575/50
=23/2=11 1/2
11 1/2

3) (11 1/2)*12 area of the one  type of the wall, there are 2 such walls
 (11 1/2)*12*2
(8 1/3)*12 area of the second type of the wall, there are 2 such walls
(8 1/3)*12 *2

Altogether area of the walls:
(11 1/2)*12*2 + (8 1/3)*12 *2=12*2(11 1/2 + 8 1/3)= =24(19+3/6+2/6)=24(19+5/6) = 456 +24*(5/6)= 456+20= 476

Tamara needs total 476  square feet, which is less than 480 square feet, so she has enough paint.



5 0
3 years ago
The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

                                         = 121 m²

Now area of the wall = 69 + 180 + 121

                                   = 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

                                                       = £105

8 0
3 years ago
A cone has a radius of 4 units and a height of 6 units.
zubka84 [21]

Answer:

Volume of the cone: 32π cubed unit

Step-by-step explanation:

Volume of cone: V=1/3hπr²

1/3 x 6 x π x 4^2 = 32π

7 0
2 years ago
Read 2 more answers
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