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Savatey [412]
3 years ago
8

Multiply (x + 3)(x – 3).

Mathematics
2 answers:
lyudmila [28]3 years ago
7 0
B would be correct the -3 x and 3 x cancel out
Lady_Fox [76]3 years ago
7 0

Answer:

The answer is B. x^2-9

Step-by-step explanation:

This problem represents a "the Sum and Difference of the same two terms".

If you encounter the same two terms and just the sign between them changes, rest assured that the result is the square of those two terms. Also, the second term will always be negative.

For example:

(a-b)*(a+b)=a^2-b^2

So, in this case:

(x+3)*(x-3)\\x^2-3*x+3*x-9\\x^2-9

Therefore, the answer is B. x^2-9

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I need the answer to all 4 questions
andreev551 [17]

Answer:

The answer to your question is:

Step-by-step explanation:

a) There is no figure 0.

b) From one figure to the other there are 2 more cubes

c) Number of cubes = 3 + 2(n- 1)

where n is the number of figure

d)

Number of cubes in figure 100 = 3 + 2(100 - 1)

                                                   = 3 + 2(99)

                                                   = 3 + 198

                                                  = 201

5 0
3 years ago
A fair number cube marked 1, 2, 3, 4, 5, and 6 is rolled. What is the chance that an even number will be rolled?
olchik [2.2K]

Answer:

50% or 1/2

Step-by-step explanation:

Chance is like probability, so the chance of rolling a even number out of  1, 2, 3, 4, 5, and 6 is half of them, they are 2, 4, and 6. In fraction form it is 1/2, and in percent form it is %0%. Hope this helps.

6 0
3 years ago
Read 2 more answers
How would you solve #2 and #3?
nordsb [41]
I think u just connect the lines
3 0
3 years ago
I need the answer I need help with this question
madreJ [45]
You can print a copy of the graph, stick a pin in the origin, and rotate it 180° to see where the figure ends up.

The origin is the midpoint between each vertex and its image.
Negate every coordinate value, for example, J(-5, -3) gets rotated to J'(5, 3).

3 0
3 years ago
Pls write the steps u did​
frez [133]

When two parallel lines are intersected by a transversal, the same-side exterior angles are supplementary. That means that their sum is 180.

Using that logic, if the two roads were parallel, then the sum of their same-side exterior angles will add up to 180. Yet their same-side exterior angles add up to 170 (130 + 40 = 170), hence they can't be parallel.

See the drawing attached below.

Using supplmenatry angles (two angles whose sum of measures add up to 180 or a straight line), we can say that:

m<DIE + m<HID = 18

40 + m<HID = 180

m<HID = 140

Similarly:

m<BHC + m<CHI = 180

130 + m<CHI = 180

m<CHI = 50

Using verticle angles therome, (when two lines intersect, the angles opposite to eachother are congruent, or have the same measure), we can say that:

m<DIE = m<GIH = 40

m<GIE = m<HID = 140

m<CHI = m<AHB = 50

m<BHC = m<AHI = 130

5 0
2 years ago
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