Answer:
1 is c and i cant see all the options for 2
Step-by-step explanation:
well first of all you have to expand the brackets. so 5(y+2)=4(x-3)
5y+10=4x-12
then you subtract 10
5y=4x-12-10=4x-22
then divide by 5 to get the value of y
y=(4x-22)/5
The -2 has a multiplicity of 2
Since the order of (x+2) is squared, i.e. power is 2
We look for the minimum of each function.
For f (x) = 3x2 + 12x + 16:
We derive the function:
f '(x) = 6x + 12
We match zero:
6x + 12 = 0
We clear the value of x:
x = -12/6
x = -2
We substitute the value of x in the equation:
f (-2) = 3 * (- 2) ^ 2 + 12 * (- 2) + 16
f (-2) = 4
For g (x) = 2sin(x-pi):
From the graph we observe that the minimum value of the function is:
y = -2
Answer:
A function that has the smallest minimum y-value is:
y = -2