Timed test

Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s

AleksAgata [21]

Answer:

Part 1) $sin(B)=\frac{21}{29}$

Part 2) $csc(A)=\frac{29}{20}$

Part 3) $cot(A)=\frac{21}{20}$

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

$sin(B)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(B)=\frac{21}{29}$

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

$csc(A)=\frac{1}{sin(A)}$

$sin(A)=\frac{BC}{AB}$ -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(A)=\frac{20}{29}$

therefore

$csc(A)=\frac{29}{20}$

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

$cot(A)=\frac{1}{tan(A)}$

$tan(A)=\frac{BC}{AC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{20}{21}$

therefore

$cot(A)=\frac{21}{20}$

4 0

3 years ago

PLEASE HELP ME!!!!!! CLICK ON THIS PLEASE

Serhud [2]

Answer:

a) ok, heres what u graph, and ur ordered pairs

graph the following points:

(0,0) (1,5) (2,10) (3,15) (4,20) (5,25) (6,30) (7,35), and so on

b) One of the ordered pairs I can use is (1,5). This is beacuse the ordered pair explains that for every video game (x), 5 will be the cost (y).

7 0

3 years ago

Read 2 more answers

Write the ratio as a fraction in simplest form.<br><br> 30 to 18

Amanda [17]

5:3. Simply by the common factor which is 6. 30 divided by 6 is five. 18 divided by 6 is 3. Therefore the simplest form is 5:3

5 0

3 years ago

Read 2 more answers

An equation that defines y as a function of x is given. a. solve for y in terms of x and

Ymorist [56]

Answer:

f(x) = 2x -2/3
f(3) = 5 1/3

Step-by-step explanation:

We solve an equation for a specific variable by using inverse operations to undo what is done to the variable. The resulting function is evaluated by substituting the given value for the variable.

__

We are given the equation ...

6x -3y = 2

Solving for y, we get ...

6x -2 = 3y . . . . . add 3y-2 to both sides

2x -2/3 = y . . . . . divide by 3

f(x) = 2x -2/3 . . . . write using functional notation

__

To find f(3), we use x=3 in the function.

f(3) = 2(3) -2/3 = 6 -2/3

f(3) = 5 1/3

4 0

2 years ago

A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses p

gizmo_the_mogwai [7]

Answer:

$t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604$

$p_v =2*P(t_{(88)}>2.604)=0.0108$

So the p value is a very low value and using any significance level for given $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

$\bar X_{1}=9.1$ represent the mean for the sample 1

$\bar X_{2}=8$ represent the mean for the sample 2

$s_{1}=1.9$ represent the sample standard deviation for the sample 1

$s_{2}=2.1$ represent the sample standard deviation for the sample 2

$n_{1}=40$ sample size for the group 1

$n_{2}=50$ sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis: $\mu_{1} = \mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

$t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604$

Statistical decision

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=40+50-2=88$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{(88)}>2.604)=0.0108$

So the p value is a very low value and using any significance level for given $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0

3 years ago