Answer:
0.0143
Step-by-step explanation:
In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.
We proceed as follows;
The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155
Let’s call this probability p
The probability that he/she isn’t on the flight, let’s call this q
q =1 - p= 0.845
Sample size, n = 155
P(X < A) = P(Z < (A - mean)/standard deviation)
Mean = np
= 125 x 0.155
= 19.375
Standard deviation = √npq
= √ (125 x 0.155x 0.845)
= 4.0462
P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)
= P(Z < (10.5 - 19.375)/4.0462)
= P(Z < -2.19)
= 0.0143
5/54 this should be your answers hope this helps
As the front approaches, you will have a storm.
I hope this helps!
Answer:
The answer is below
Step-by-step explanation:
a) The baseball player leaps into the air with an initial velocity of 14 feet per second. This means that the player leaps from the ground, the initial height is therefore zero.
The height (y) is given by the formula:
y(t) = ut - (1/2)gt² + initial heigth
u = initial velocity = 14 ft/s, t = time taken, g = acceleration due to gravity = 32 ft/s². Substituting:
y(t) = 14t - (1/2) * 32 *t² + 0
y(t) = 14t - 16t²
b) when the player is on the ground, the height = 0. hence:
0 = 14t - 16t²
16t² - 14t = 0
t(16t - 14) = 0
t = 0 or 16t - 14 = 0
t = 0 or 16t = 14
t =0 or t = 0.875
Hence t = 0.875 seconds
c) The domain is the set of possible values for the time. Hence:
Domain = (0, 0.875] = 0 < t ≤ 0.875
