Answer:
18.58 moles of Cu
Solution:
Data Given:
Chemical Formula of Tennantite = Cu₁₂As₄S₁₃
Mass of Cu₁₂As₄S₁₃ = 2290 g
M.Mass of Cu₁₂As₄S₁₃ = 1479.06 g.mol⁻¹
Step 1: Calculate Moles of Cu₁₂As₄S₁₃ as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 2290 g ÷ 1479.06 g.mol⁻¹
Moles = 1.548 mol
Step 2: Calculate Moles of Cu,
As,
1 mole of Cu₁₂As₄S₁₃ contains = 12 moles of Cu
So,
1.548 mol of Cu₁₂As₄S₁₃ will contain = X moles of Cu
Solving for X,
X = (1.548 mol × 12 mol) ÷ 1 mol
X = 18.58 moles of Cu
Answer:
41.54 grams of oxygen are required to burn 13.5 g of acetylene
Explanation:
The balanced reaction is:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- C₂H₂: 2 moles
- O₂: 5 moles
- CO₂: 4 moles
- H₂O: 2 moles
Being the molar mass of the compounds:
- C₂H₂: 26 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- C₂H₂: 2 moles* 26 g/mole= 52 grams
- O₂: 5 moles* 32 g/mole= 160 grams
- CO₂: 4 moles* 44 g/mole= 176 grams
- H₂O: 2 moles* 18 g/mole= 36 grams
You can apply the following rule of three: if by stoichiometry 52 grams of acetylene react with 160 grams of oxygen, 13.5 grams of acetylene react with how much mass of oxygen?

mass of oxygen= 41.54 grams
<u><em>41.54 grams of oxygen are required to burn 13.5 g of acetylene</em></u>
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