- The following reaction is an example of <u>FUSION</u>:
2 1 H + 1 1 h → 3 2 He + energy
<em>(The answer is</em> fusion<em>) </em>
<span>Sand dunes are formed from wind
movement. There needs to be a large amount of loose sand in an area with
hardly any vegetation, enough wind to move grains of sand and some kind
of obstacle to make the blowing sand lose its momentum and settle in a
new place</span>
Answer:
129,66 g
Explanation:
Desde,
Número de moles = concentración * volumen
concentración = 2 M
volumen = 875 ml
Número de lunares = 2 * 875/1000
Número de lunares = 1,75 moles
Número de moles = masa / masa molar
masa molar de hidróxido de calcio = 74.093 g / mol
1,75 moles = masa / 74,093 g / mol
masa = 1,75 moles * 74,093 g / mol
masa = 129,66 g
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>
<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>
Molarity is used to measure the concentration of a solution , so it is also as molar concentration. It is denoted as M or Mol/L
<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>
- Weight of = 5.34g
- Volume of solution = 214 ml , or 0.214 L
The molar mass of magnesium chloride ( ) is 95.21 g / mol
We can calculate the molarity of the solution by dividing the number of moles of solute by volume of solvent in liter ,i.e:
ㅤㅤㅤ⸻( 1 )
<em>Where,</em><em> </em>
- M = molarity
- n = number of moles
- V = Volume
We can calculate the number of moles by dividing the actual mass by its molar mass ,i.e:
ㅤㅤㅤ⸻ ( 2 )
<em>W</em><em>here,</em>
- n = number of moles
- m = molar mass
- w = actual mass
<u>Therefore</u><u>,</u>
<u>P</u><u>utting </u><u>the </u><u>values </u><u>in </u><u>equation </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u>
Answer:
The answer to your question is: 516 g of water
Explanation:
2 C₇H₁₄ + 21 O₂ → 14 CO₂ + 14 H₂O
8 moles 43 moles
Process
1.- Find the limiting reactant
Ratio theoretical O₂ / C₇H₁₄ = 21 / 2 = 10.5
Ratio experimental O₂ / C₇H₁₄ = 43 / 8 = 5.3
As the ratio diminishes the limiting reactant is O₂.
2.- Calculate the moles of water
21 moles of O₂ ------------- 14 moles of water
43 moles of O₂ ------------ x
x = (43 x 14) / 21
x = 28.67 moles of water
3.- Calculate the grams of water
Molecular mass of water= 18g
18 g ------------------------ 1 mol of water
x ------------------------ 28.67 moles of water
x = (28.67 x 18) / 1
x = 516 g of water