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zloy xaker [14]
2 years ago
7

Anna made a scale drawing, in inches, of a building using a scale of 1:600 . Her scale drawing was 6 inches long. Greg made a sc

ale drawing of the same building using a scale of 1:300 How long, in inches, was Greg's scale drawing?
Mathematics
1 answer:
Marizza181 [45]2 years ago
7 0

Answer:

1200 inches

Step-by-step explanation:

Given that:

Scale used by Anna in her drawings = 1 : 600

Length of drawing made by Anna of a building = 6 inches

Scale used by Greg in the drawing = 1 : 300

To find:

The length of scale drawing made by Greg.

Solution:

Here, we first need to find the original length of the building so that we can find the length of scale drawing made by Greg.

Ratio 1 : 600 means 600 is the actual length of building, if the length of scale drawing is 1.

Here, we are given length of scale drawing as 6 inches, therefore the actual length of building = 6 \times 600 = 3600 inches

Now, applying the ratio 1 : 300, we get the length of scale drawing by Greg as \frac{3600}{3} = <em>1200 inches</em>

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Geometry. Attached photo. PLEASE FOR THE LOVE OF GOD.
kupik [55]

Answer:

m<C = 42°

Step-by-step explanation:

Given:

m<A = (2x - 2)°

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m<DBC = m<A + m<C (exterior angle theorem of a triangle)

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Can someone plz help me out
Shkiper50 [21]
2.false. This is so as 3 to 4 or 3/4=0.75 while 4 to 3 is 1.333333333333333 infinite. 
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3 years ago
A particular battery claims to have a mean life of 400 hours with a standard deviation of 30 hours. Approximately what percent o
Svetach [21]

Using the normal distribution, it is found that 25.14% of the batteries will last more than 420 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, we have that the mean and the standard deviation are given, respectively, by:

\mu = 400, \sigma = 30.

The proportion of the batteries will last more than 420 hours is <u>one subtracted by the p-value of Z when X = 420</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{420 - 400}{30}

Z = 0.67

Z = 0.67 has a p-value of 0.7486.

1 - 0.7486 = 0.2514.

0.2514 = 25.14% of the batteries will last more than 420 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

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2 years ago
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