Option C: np is the expression used for calculating the mean of a binomial distribution.
Explanation:
From the options, we need to determine the expression that is used for calculating the mean of a binomial distribution.
<u>Option A: npq</u>
The variance of the binomial distribution can be calculated using the expression npq.
Hence, Option A is not the correct answer.
<u>Option B: </u>
<u></u>
The standard deviation of the binomial distribution can be calculated using the expression ![\sqrt{npq}](https://tex.z-dn.net/?f=%5Csqrt%7Bnpq%7D)
Hence, Option B is not the correct answer.
<u>Option C: np</u>
The mean of the binomial distribution can be calculated using the expression np
Hence, Option C is the correct answer.
<u>Option D</u>: ![\sum\left[x^{2} \cdot P(x)\right]-\mu^{2}](https://tex.z-dn.net/?f=%5Csum%5Cleft%5Bx%5E%7B2%7D%20%5Ccdot%20P%28x%29%5Cright%5D-%5Cmu%5E%7B2%7D)
The mean of the binomial distribution cannot be determined using the expression ![\sum\left[x^{2} \cdot P(x)\right]-\mu^{2}](https://tex.z-dn.net/?f=%5Csum%5Cleft%5Bx%5E%7B2%7D%20%5Ccdot%20P%28x%29%5Cright%5D-%5Cmu%5E%7B2%7D)
Hence, Option D is not the correct answer.
Answer:
no es un elemento de la tabla periódica
Answer:
34.01
Step-by-step explanation:
Circumference = Diameter * π
106.81 = Diameter * π
Diameter = 34.01
Answer:
Step-by-step explanation:
![p {t}^{2} = \frac {2x - pm}{2} \\ 2pt^2 = 2x - pm\\2pt^2 +pm= 2x \\p(2t^2 +m) =2x\\\\\huge\purple {\boxed {p = \frac {2x}{(2t^2 +m)}}} \\](https://tex.z-dn.net/?f=p%20%7Bt%7D%5E%7B2%7D%20%20%3D%20%5Cfrac%20%7B2x%20-%20pm%7D%7B2%7D%20%5C%5C%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E2pt%5E2%20%3D%202x%20-%20pm%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E2pt%5E2%20%2Bpm%3D%202x%20%5C%5C%3C%2Fp%3E%3Cp%3Ep%282t%5E2%20%2Bm%29%20%3D2x%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%5Chuge%5Cpurple%20%7B%5Cboxed%20%7Bp%20%3D%20%5Cfrac%20%7B2x%7D%7B%282t%5E2%20%2Bm%29%7D%7D%7D%20%3C%2Fp%3E%3Cp%3E%20%5C%5C%20)
Answer:
Nth term= dn+(a-d)
Step-by-step explanation:
D is the difference between the terms
A is the first term
N is the term number