In which table is y a LINEAR function of x? A B C D

Chloe spent $69 and now has no money left. She had before her purchase. She had $ before her purchase. can you please help me wi

max2010maxim [7]

Answer:

$69

Step-by-step explanation:

Given

$Purchase = \$69$

$Amount\ Left = \$0$

Required

Determine the cash before purchase

To get the her amount before the purchase, we simply add both given parameters together.

This is done as follows;

$Amount = Amount Left + Purchase$

Substitute 0 for Amount Left and 60 for Purchase

$Amount = \$0 + \$69$

$Amount = \$69$

Hence, she had $69 before the purchase

6 0

3 years ago

This one is the one I need help with my final question

STatiana [176]

Answer:

vertex C could be at (6,0) or (2,8)

(I'm sorry if I'm wrong, but if not I hope this helps!)

Step-by-step explanation:

vertex C needs to be placed somewhere on the graph where it would form a right angle (and therefore a right-angled triangle as well). vertex C could be at (6,0) or (2,8). this is because at these two points vertex C will form a right angle, therefore making it a right-angled triangle.

7 0

3 years ago

I need help pls I WILL GIVE BRAINLIEST Pls help

uranmaximum [27]

Answer:

1. The square root of 100

2.c=27.11

d=13.96

e=12.6

Step by step explanation: 

1. 2×50=100 the geometric mean is the square root of 100

2. The diagram is made up of three right angled triangles the big outer one and two triangles inside the big one thus we can use the pythagorean theorem to come up with expressions which will help us in solving the unknown parts as below.

c²=30²-d²

c²=e²+24²

d²=e²+6²

both the following add up to c² meaning they are equal:

c²=30²-d²

c²=e²+24²

thus

30²-d²=e²+24²

I want to remain with d² only thus;

30²-24²-e²=d²

900-576=324 (squareroot of 324=18) so

d²=18²-e² and d²=e²+6²

both the above add up to d² meaning they are equal thus;

18²-e²=e²+6²

18²-6²=e²+e²

324-36=2e²

318=2e²

159=e²

e=12.61

Thus d²=e²+6²

d²=12.61²+6²

d²=159+36

d²=195

d=13.96

c²=e²+24²

c²=12.61²+24²

c²=159+576

c²=735

c=27.11

 

I hope this helps

3 0

3 years ago

The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:

blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

$SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}$

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}$

$=\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182$

Compute the standard deviation as follows:

$SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}$

$=\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899$

Thus, the standard deviation of the age distribution is 6.2899 years.

7 0

3 years ago

List the next four multiples of the fraction. 3/6

Arlecino [84]

They are 6/6, 9/6, 12/6, and 15/6. Please give brainliest!!!

6 0

2 years ago

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