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11111nata11111 [884]
2 years ago
9

Show that the following rectangular form x^2+y^2=2xy can be expressed as 1 = sin(2) in polar form.

Mathematics
1 answer:
lara [203]2 years ago
7 0

Answer:

Step-by-step explanation:

substitute x = r*cos(θ), y = r*sin(θ) ==> r²(cos²(θ) + sin²(θ)) = 2r²cos(θ)sin(θ). Cancel the r² on both sides. On the left, use pythagorean identity cos²(θ) + sin²(θ) = 1. On the right apply double angle identity sin(2θ) = 2cos(θ)sin(θ).

This yields 1=sin(2θ). (I assume you meant to type sin(2θ) on the right hand side of the equation).

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Answer:

Step-by-step explanation:

x + 2y + 3z = 12

z=\frac{12-x-2y}{3}

Volume = V=f(x,y) = xy(\frac{12-x-2y}{3} )

find partial derivatives using product rule

f_x =\frac{y}{3} (12-2x-2y)\\f_y = \frac{x}{3} (12-x-4y)

i.e.

Using maximum for partial derivatives, we equate first partial derivative to 0.

y=0 or x+y =6

x=0 or x+4y =12

Simplify to get y =2, x = 4

thus critical points are (4,2) (6,0) (0,3)

Of these D the II derivative test gives

D<0 only for (4,2)

Hence maximum volume is when x=4, y=2, z= 4/3

Max volume is = 4(2)(4/3) = 32/3

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8 0
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What is the slope of -2x + 4y = 12 ?
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Step-by-step explanation:

6 0
3 years ago
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Step-by-step explanation:

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Answer:

d) 12(100) + 12(80) + 12(5)

Step-by-step explanation:

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12(185)=12(100+80+5)

We expand using the distributive property to get;

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