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11111nata11111 [884]
2 years ago
9

Show that the following rectangular form x^2+y^2=2xy can be expressed as 1 = sin(2) in polar form.

Mathematics
1 answer:
lara [203]2 years ago
7 0

Answer:

Step-by-step explanation:

substitute x = r*cos(θ), y = r*sin(θ) ==> r²(cos²(θ) + sin²(θ)) = 2r²cos(θ)sin(θ). Cancel the r² on both sides. On the left, use pythagorean identity cos²(θ) + sin²(θ) = 1. On the right apply double angle identity sin(2θ) = 2cos(θ)sin(θ).

This yields 1=sin(2θ). (I assume you meant to type sin(2θ) on the right hand side of the equation).

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grigory [225]
Y = 3x - 2
-3x + y = -2
-3x = -y - 2
x = (1/3)y + 2/3
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3 years ago
10. And 11. Please help right now
Thepotemich [5.8K]
10.
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3 years ago
What is the correct way to label the entire line segment shown​
Simora [160]

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Step-by-step explanation:

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2 years ago
A monopolist faces the demand function P = 140 − 2Q, with P denoting the market price and Q denoting the quantity demanded.
devlian [24]

Answer:

a) The profit function is P(Q)= -13Q^3 +8Q^2-44Q

b) The derivative of the profit function is P \,'(Q)=-39Q^2 +16Q-44

c) There are no values for Q where P \, '(Q)= 0.

Step-by-step explanation:

The Profit function is defined as the difference between Revenue function and Cost function, where the Revenue function is defined as the price times the number of products.

So starting with the revenue we have:

R(Q)=PQ

where P is the market price and Q the quantity demanded, using the demand function we can write:

R(Q)=(140-2Q)Q

a) Thus the Profit function is

P(Q)=R(Q)-C(Q)\\\\P(Q)=140Q-2Q^2 -(13Q^3-10Q^2 +188Q)\\\\P(Q)=140Q-2Q^2 -13Q^3+10Q^2-188Q\\\\P(Q)= -13Q^3 +8Q^2-44Q

b) We can determine the derivative of the profit function using the result on part a).

P(Q)= -13Q^3 +8Q^2-44Q\\P \,'(Q)=-39Q^2 +16Q-44

c) We can set the profit function equal to 0

P \, '(Q)= 0

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Since we cannot factor we will have to use quadratic formula.

Q = \cfrac{-b\pm \sqrt{b^2-4ac}}{2a}

where the coefficients are

a=-39\\b = 16\\ c=-44

So we get

Q = \cfrac{-16\pm \sqrt{16^2-4(-39)(-44)}}{2(-39)}

Notice that we get a negative number inside the square root if we evaluate it.

Q = \cfrac{-16\pm \sqrt{-6608}}{2(-39)}

Since we get a negative number inside the root, then there are no real values of Q where the derivative of the profit function is equal to 0.

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