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2 years ago

Pls answer to this question....How do we find the key of a Stem And Leafe diagram ?

1 answer:

5 0

➠The key tells the reader what values are represented in the display. To do this, select one term in the plot and separate the digits by a vertical line, then use the equal sign to show what it is equivalent to. It will look like this, 6|8=68.

$\mathbf\fcolorbox{blue}{gray}{BE \: BRAINLY}$

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HELP NEED PRECALC HELP WILL GIVE BRAINLIEST PLEASE HELP

Shalnov [3]

From your earlier questions, we found

$2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)$

so the wave has amplitude √29. The weight's maximum negative position from equilibrium is then -√29, so you are solving for t in the given interval for which

$\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)=-\dfrac{\sqrt{29}}2$

Divide both sides by √29:

$\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)=-\dfrac12$

Take the inverse sine of both sides, noting that we get two possible solution sets because we have

$\sin\left(\dfrac{7\pi}6\right)=\sin\left(\dfrac{11\pi}6\right)=-\dfrac12$

and the sine wave has period 2π, so $\sin x=\sin(x+2\pi)=\sin(x+4\pi)=\cdots$ .

$\implies 4\pi t+\tan^{-1}\left(\dfrac52\right)=\dfrac{7\pi}6+2n\pi$

$\implies 4\pi t+\tan^{-1}\left(\dfrac52\right)=\dfrac{11\pi}6+2n\pi$

where n is any integer.

Now solve for t :

$t=\dfrac{\frac{7\pi}6+2n\pi-\tan^{-1}\left(\frac52\right)}{4\pi}$

$t=\dfrac{\frac{11\pi}6+2n\pi-\tan^{-1}\left(\frac52\right)}{4\pi}$

We get solutions between 0 and 0.5 when n = 0 of t ≈ 0.196946 and t ≈ 0.363613.

6 0

3 years ago

Savannah owns a food truck that sells tacos and burritos. She only has enough supplies to make 150 tacos or burritos. She sells

trapecia [35]

Answer:

Graph y≤150−x (shading down)

Graph y≥120− 7/11x (shading up)

Step-by-step explanation:

8 0

4 years ago

18 х 49° A) 13.6 C) 23.9 B) 19.7 D) 8.9

olasank [31]

Answer:

the answer is c 23.9

i hope it helps

8 0

3 years ago

Read 2 more answers

A randomized study compared two different systems for tracking baggage at an airport. The treatment group using System A reporte

Natasha2012 [34]

Answer:

D. The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

Step-by-step explanation:

The treatment group using System A reported a mean of 18.5 lost bags per day. The treatment group using System B reported a mean of 16.6 lost bags per day.

The best conclusion that can be made is - The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

As we know, in statistics, nothing happens by chance. So, this option is correct.

8 0

3 years ago

Read 2 more answers

Hugo averages 58 words per minute on a typing test with a standard deviation of 11 words per minute. Suppose Hugo's words per mi

Black_prince [1.1K]

Answer:

The number of words that Hugo wrote in the test of Wednesday (74) is at a distance of 1.4545 standard deviations (11) to the right of his mean (58)

Step-by-step explanation:

A normal random variable with mean Mu = 58 and standard deviation sd = 11 is standardized with the transformation (z-score):

Z = (X - Mu) / sd = (X - 58) / 11

For a value of 74 for X, Z = (74 - 58) / 11 = 1.4545 > 0.

The z-score when X = 74 is 1.4545 > 0

This means that the number of words that Hugo wrote in the test of Wednesday (74) is at a distance of 1.4545 standard deviations (11) to the right of his average (58)

6 0

3 years ago

Pls answer to this question....How do we find the key of a Stem And Leafe diagram ? ​

Pls answer to this question....How do we find the key of a Stem And Leafe diagram ?