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Area of the rectangular mat = 12 x 4 = 48 in²
Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²
P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)
Answer: The probability of landing in one of the circles is 0.79.
Answer:
Step-by-step explanation:
First we know triangle WXY is an equilateral which means all its angles are 60 degrees.
Next we know triangle WZY is an isosceles so it has 2 angles that are equal to each other.
Since angle Z is an obtuse angle. We can calculate the other angles which we will assume are equal because 138+138 is greater than 180 degrees.
180-138 = 42
42/2 = 21 <-- divide by 2 because we know we're looking for 2 angles
For the angles of WXY.
60-21 = 39
Therefore
Angle I = 60
Angle 2 = 39
Angle 3 = 21
Angle 4 = 39
Angle 5 = 21
5/8 =
2.5/4=
62.5/100=
62.5%